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Question

A value of x that satisfies the equation $ \log x + \log (x - 7) = \log (x + 11) + \log 2 $ is

The correct answer is
11

Solving the Logarithmic Equation

The problem requires finding the value of x that satisfies the given logarithmic equation:

$ \log x + \log (x - 7) = \log (x + 11) + \log 2 $

Applying Logarithm Properties

Use the logarithm property $ \log a + \log b = \log (ab) $ to simplify both sides of the equation.

  • Left side: $ \log (x(x - 7)) $
  • Right side: $ \log (2(x + 11)) $

The equation becomes:

$ \log (x(x - 7)) = \log (2(x + 11)) $

Equating Arguments and Solving

Since the logarithms are equal, their arguments must be equal:

$ x(x - 7) = 2(x + 11) $

Expand both sides:

$ x^2 - 7x = 2x + 22 $

Rearrange into a standard quadratic equation ($ ax^2 + bx + c = 0 $):

$ x^2 - 7x - 2x - 22 = 0 $

$ x^2 - 9x - 22 = 0 $

Factor the quadratic equation:

$ (x - 11)(x + 2) = 0 $

This gives two potential solutions: $ x = 11 $ or $ x = -2 $.

Checking Domain Restrictions

The argument of a logarithm must always be positive.

  • For $ \log x $, we need $ x > 0 $.
  • For $ \log (x - 7) $, we need $ x - 7 > 0 $, which means $ x > 7 $.
  • For $ \log (x + 11) $, we need $ x + 11 > 0 $, which means $ x > -11 $.

To satisfy all conditions, x must be greater than 7 ($ x > 7 $).

Validating Potential Solutions

Evaluate the potential solutions against the domain requirement ($ x > 7 $):

  • If $ x = 11 $: $ 11 > 7 $. This solution is valid.
  • If $ x = -2 $: $ -2 $ is not greater than 7. This solution is extraneous and must be discarded.

Therefore, the only value of x that satisfies the original equation is 11.

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Important Questions from Logarithms

  1. Real numbers $y$, $p$, and $n$ (all greater than 1) satisfy
    $$(\log_{p^{1/n}} y)(\log_{y^{1/n}} p) = 16,$$
    where the logarithms are taken to the bases $p^{1/n}$ and $y^{1/n}$.
    The value of $n$ is ________
  2. Consider two distinct positive real numbers $m, n$, with $m > n$.

    Let $x = n^{\log_{10}(m)}$ and $y = m^{\log_{10}(n)}$. The relation between $x$ and $y$ is _______.

  3. If $\log_x (5/7) = -1/3$, then the value of $x$ is
  4. For a real number $x > 1$, 
    $\frac{1}{\log_2 x} + \frac{1}{\log_3 x} + \frac{1}{\log_4 x} = 1$ 
    The value of $x$ is

  5. Let $a = 30!$, $b = 50!$, and $c = 100!$. Consider the following numbers: 

    $log_a c$,           $log_c a$,           $log_b a$,             $log_a b$ 

    Which one of the following inequalities is CORRECT?

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