A tower stands vertically on the ground. From a point on the ground which is 18 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 30°. Find the height of the tower.
5√3 m
This problem involves finding the height of a tower using trigonometry, specifically the concept of the angle of elevation. When we look up at the top of a tower from a point on the ground, the angle between the horizontal line (the ground) and the line of sight to the top of the tower is called the angle of elevation.
We can visualize this situation as forming a right-angled triangle. The vertical side of the triangle represents the height of the tower, the horizontal side represents the distance from the point on the ground to the foot of the tower, and the hypotenuse is the line of sight from the point to the top of the tower.
In the right-angled triangle formed:
The trigonometric ratio that relates the opposite side and the adjacent side to an angle in a right-angled triangle is the tangent function.
The formula is:
\(\tan(\theta) = \frac{\text{Opposite Side}}{\text{Adjacent Side}}\)
Substituting the known values and the unknown height (h):
\(\tan(30^\circ) = \frac{h}{15}\)
We know the value of \(\tan(30^\circ)\) from standard trigonometric values:
\(\tan(30^\circ) = \frac{1}{\sqrt{3}}\)
Now substitute this value into our equation:
\(\frac{1}{\sqrt{3}} = \frac{h}{15}\)
To find 'h', we can cross-multiply or multiply both sides by 15:
\(h = 15 \times \frac{1}{\sqrt{3}}\)
\(h = \frac{15}{\sqrt{3}}\)
To rationalize the denominator (remove the square root from the bottom), we multiply both the numerator and the denominator by \(\sqrt{3}\):
\(h = \frac{15}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\)
\(h = \frac{15\sqrt{3}}{3}\)
Now, simplify the expression:
\(h = 5\sqrt{3}\)
The height of the tower is \(5\sqrt{3}\) m.
| Ratio | Definition | Formula |
|---|---|---|
| Sine (sin) | Opposite side / Hypotenuse | \(\sin(\theta) = \frac{\text{Opposite}}{\text{Hypotenuse}}\) |
| Cosine (cos) | Adjacent side / Hypotenuse | \(\cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}}\) |
| Tangent (tan) | Opposite side / Adjacent side | \(\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}}\) |
Angle of Elevation: This is the angle measured upwards from the horizontal line to the line of sight of an object above the horizontal level. In our problem, looking up at the top of the tower creates an angle of elevation.
Angle of Depression: This is the angle measured downwards from the horizontal line to the line of sight of an object below the horizontal level. If you were at the top of the tower looking down at the point on the ground, that would be the angle of depression. The angle of elevation from point A to point B is always equal to the angle of depression from point B to point A, assuming they are at different heights.
These concepts are widely used in real-world applications like surveying, navigation, and architecture to calculate heights and distances that cannot be measured directly.
Match List I with List II.
| List I | List II |
|---|---|
| (A) \( \frac{14 - (x - 1)}{10} = \frac{x + 5}{6} - 3 \) | (I) 4 |
| (B) \( (x - 5)^2 - (x + 3)^2 = 48 \) | (II) \( 23^2 \) |
| (C) \( 6(x - 4) = 4(x - 3) - 3(x - 8) \) | (III) 61 |
| (D) \( (2x - 1)(2x + 3) = (2x - 7)(2x + 7) \) | (IV) -2 |
Choose the correct answer from the options given below:
Asha is twice as old as Anita. Three years ago, she was three times as old as Anita. How old is Asha now?
A cube painted green on all faces is cut into 27 small cubes of equal size. How many small cubes are painted on one face only?
Arrange the given events in ascending order of their probabilities:
A = target is hit 2 times in 20 shots
B = target is hit 175 times in 200 shots
C = target is hit 92 times in 100 shots
D = target is hit 2 times in 5 shots
E = target is hit 5 times in 13 shots
Choose the correct answer from the options given below:
Given below are two statements:
Statement I: Only one Rhombus ABCD can be drawn with AB = 4 cm and diagonal BD = 5 cm.
Statement II: Only one parallelogram ABCD can be drawn with AB = 6 cm and diagonal BD = 8 cm.
In the light of the above statements, choose the correct answer from the options given below: