A tile drainage system draining 12 hectares flows at a design capacity for two days, following a storm. If the system is designed using a D.C. of 1.25 cm/day, how many cubic meters of water will be removed during this period?
3000 m 3
Calculating Water Volume Removed by Tile Drainage
This problem asks us to calculate the total volume of water removed by a tile drainage system over a specific period, given the drainage area, the design capacity (D.C.), and the duration.
Understanding Tile Drainage and Design Capacity
A tile drainage system is used in agricultural fields to remove excess water from the soil profile. The design capacity (D.C.) of such a system indicates the rate at which it is designed to remove water, typically expressed as a depth of water removed per day over the drainage area. For example, a D.C. of 1.25 cm/day means the system is designed to remove a depth of 1.25 centimeters of water from the entire drained area each day.
Given Information:
- Drainage area: 12 hectares
- Design capacity (D.C.): 1.25 cm/day
- Duration of flow at design capacity: 2 days
Calculating the Total Depth of Water Removed
The design capacity gives the depth removed per day. To find the total depth removed over 2 days, we multiply the D.C. by the duration:
\[ \text{Total depth} = 1.25 \text{ cm/day } \times 2 \text{ days} = 2.5 \text{ cm} \]Converting Units
To calculate the volume in cubic meters, we need to convert the area from hectares to square meters and the depth from centimeters to meters.
- Conversion of Area: 1 hectare = 10,000 m2
- Conversion of Depth: 1 cm = 0.01 m
So, the drainage area in m2 is:
\[ \text{Area} = 12 \text{ hectares } \times 10,000 \text{ m}^2\text{/hectare } = 120,000 \text{ m}^2 \]And the total depth removed in meters is:
\[ \text{Total depth} = 2.5 \text{ cm } \times 0.01 \text{ m/cm } = 0.025 \text{ m} \]Calculating the Total Volume of Water Removed
The volume of water removed is the area multiplied by the total depth of water removed over that area:
Volume = Area × Total depth
Using the values in meters and square meters:
\[ \text{Volume} = 120,000 \text{ m}^2 \times 0.025 \text{ m} \]Performing the multiplication:
\[ 120,000 \times 0.025 = 120,000 \times \frac{25}{1000} = 120 \times 25 = 3000 \]So, the total volume of water removed is 3000 m3.
Summary of Calculation Steps:
| Step | Description | Calculation |
|---|---|---|
| 1 | Total depth removed over 2 days | 1.25 cm/day × 2 days = 2.5 cm |
| 2 | Convert Area to m2 | 12 hectares × 10,000 m2/hectare = 120,000 m2 |
| 3 | Convert Total depth to m | 2.5 cm × 0.01 m/cm = 0.025 m |
| 4 | Calculate Volume (Area × Total depth) | 120,000 m2 × 0.025 m = 3000 m3 |
Thus, 3000 cubic meters of water will be removed by the tile drainage system during the two-day period.
Important Questions from Water Logging and Reclamation
- Leaching is a process:
Under Benefits of Irrigation,
Statement 1:- yield of crops can be increased by irrigation even in a period of low rainfall.
Statement 2:- optimum use of water is possible by irrigation to obtain maximum output.
A tile drain is laid below a cropped land to remove excess irrigation water, the drainage coefficient of this drain is usually expressed as:
Which factor leads to waterlogging due to obstruction?
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