A tile drainage system draining 12 hectares flows at a design capacity for two days, following a storm. If the system is designed using a D.C. of 1.25 cm/day, how many cubic meters of water will be removed during this period?
3000 m 3
Calculating Water Volume Removed by Tile Drainage
This problem asks us to calculate the total volume of water removed by a tile drainage system over a specific period, given the drainage area, the design capacity (D.C.), and the duration.
Understanding Tile Drainage and Design Capacity
A tile drainage system is used in agricultural fields to remove excess water from the soil profile. The design capacity (D.C.) of such a system indicates the rate at which it is designed to remove water, typically expressed as a depth of water removed per day over the drainage area. For example, a D.C. of 1.25 cm/day means the system is designed to remove a depth of 1.25 centimeters of water from the entire drained area each day.
Given Information:
- Drainage area: 12 hectares
- Design capacity (D.C.): 1.25 cm/day
- Duration of flow at design capacity: 2 days
Calculating the Total Depth of Water Removed
The design capacity gives the depth removed per day. To find the total depth removed over 2 days, we multiply the D.C. by the duration:
\[ \text{Total depth} = 1.25 \text{ cm/day } \times 2 \text{ days} = 2.5 \text{ cm} \]Converting Units
To calculate the volume in cubic meters, we need to convert the area from hectares to square meters and the depth from centimeters to meters.
- Conversion of Area: 1 hectare = 10,000 m2
- Conversion of Depth: 1 cm = 0.01 m
So, the drainage area in m2 is:
\[ \text{Area} = 12 \text{ hectares } \times 10,000 \text{ m}^2\text{/hectare } = 120,000 \text{ m}^2 \]And the total depth removed in meters is:
\[ \text{Total depth} = 2.5 \text{ cm } \times 0.01 \text{ m/cm } = 0.025 \text{ m} \]Calculating the Total Volume of Water Removed
The volume of water removed is the area multiplied by the total depth of water removed over that area:
Volume = Area × Total depth
Using the values in meters and square meters:
\[ \text{Volume} = 120,000 \text{ m}^2 \times 0.025 \text{ m} \]Performing the multiplication:
\[ 120,000 \times 0.025 = 120,000 \times \frac{25}{1000} = 120 \times 25 = 3000 \]So, the total volume of water removed is 3000 m3.
Summary of Calculation Steps:
| Step | Description | Calculation |
|---|---|---|
| 1 | Total depth removed over 2 days | 1.25 cm/day × 2 days = 2.5 cm |
| 2 | Convert Area to m2 | 12 hectares × 10,000 m2/hectare = 120,000 m2 |
| 3 | Convert Total depth to m | 2.5 cm × 0.01 m/cm = 0.025 m |
| 4 | Calculate Volume (Area × Total depth) | 120,000 m2 × 0.025 m = 3000 m3 |
Thus, 3000 cubic meters of water will be removed by the tile drainage system during the two-day period.
Important Questions from Water Logging and Reclamation
- Water logging may result from -
Which of the following statements is INCORRECT?
A. Seepage drains reduce the chances of water logging.
B. Water logging makes the land more productive.
C. Fertilisers used in irrigation may contribute in various ways to the problem of water pollution.
D. Water logging is caused due to the presence of permeable strata.
- Leaching is a process:
Water logging occurs when the water table is
The suitable method for irrigating highly undulating land is
