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Question

A thin cylinder of inner radius 500 mm and thickness 10 mm is subjected to an internal pressure of 5 MPa. The average circumferential (hoop) stress in MPa is

The correct answer is

250

Thin Cylinder Hoop Stress Calculation

Understanding the stress distribution in thin-walled cylinders, like pressure vessels or pipes, is a fundamental concept in mechanics of materials. When a thin cylinder is subjected to internal pressure, two primary types of stresses are developed: circumferential (or hoop) stress and longitudinal (or axial) stress. This problem focuses on calculating the average circumferential (hoop) stress.

Given Parameters for Thin Cylinder Stress

Let's identify the given values for the thin cylinder from the problem statement:

  • Inner radius of the cylinder, \(r = 500 \text{ mm}\)
  • Thickness of the cylinder wall, \(t = 10 \text{ mm}\)
  • Internal pressure applied to the cylinder, \(p = 5 \text{ MPa}\)

Formula for Circumferential (Hoop) Stress

For a thin-walled cylinder, where the ratio of the inner radius to the wall thickness (\(r/t\)) is typically greater than 10, the average circumferential or hoop stress (\(\sigma_h\)) can be calculated using a simplified formula. This formula assumes uniform stress distribution across the wall thickness, which is a reasonable approximation for thin cylinders.

The formula for the average circumferential (hoop) stress in a thin cylinder is:

\[\sigma_h = \frac{pr}{t}\]

Where:

  • \(\sigma_h\) is the circumferential (hoop) stress
  • \(p\) is the internal pressure
  • \(r\) is the inner radius
  • \(t\) is the wall thickness

Step-by-Step Calculation of Hoop Stress

Now, let's substitute the given values into the formula to find the average circumferential (hoop) stress. It's important to ensure that all units are consistent. In this case, pressure is in MPa, and dimensions are in mm, which will yield stress in MPa.

Parameter Value
Internal Pressure (\(p\)) \(5 \text{ MPa}\)
Inner Radius (\(r\)) \(500 \text{ mm}\)
Thickness (\(t\)) \(10 \text{ mm}\)

Substitute these values into the formula:

\[\sigma_h = \frac{(5 \text{ MPa}) \times (500 \text{ mm})}{10 \text{ mm}}\]

First, multiply the pressure by the inner radius:

\[\sigma_h = \frac{2500 \text{ MPa} \cdot \text{mm}}{10 \text{ mm}}\]

Now, divide by the thickness:

\[\sigma_h = 250 \text{ MPa}\]

Final Result for Circumferential Stress

The calculated average circumferential (hoop) stress in the thin cylinder subjected to an internal pressure of 5 MPa is 250 MPa. This value represents the tensile stress acting along the circumference of the cylinder due to the internal pressure.

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Important Questions from Analysis of Thin Cylinder

  1. The longitudinal stress induced in a thin-walled cylindrical vessel of diameter D, thickness t, under pressure P is

  2. If the thin cylindrical shell whose diameter is 'd' is subjected to an internal pressure 'p', then the ratio of longitudinal stress to the hoop stress is-

  3. If the thickness of the wall of the cylindrical vessel is less than ________ of its internal diameter, the cylindrical vessel is known as a thin cylinder.

  4. A seamless pipe is to carry a fluid under a pressure of 2 N/mm2. The thickness of the cylinder is 10 mm. Calculate the diameter of the pipe if the maximum stress allowed is 100 N/mm2.

  5. The circumferential stress is given by:

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