A thief pursued by a policeman was 150 m ahead at the start. If the ratio of the speed of the policeman to that of the thief was 5:4, then how far (distance in metres) could the thief go before he is caught by the policeman?
300
The relative speed between the policeman and the thief is (5 - 4) = 1 unit (since the ratio of their speeds is 5:4).
The distance the thief gets ahead is 150 meters.
Since the relative speed is 1 unit, the time it takes for the policeman to catch up is 150 meters / 1 unit = 150 meters.
In this time, the thief will have covered 150 meters at a speed of 4 units, so the thief will cover:
150 × (4/1) = 600 meters before being caught.
Thus, the correct answer is option 2: 300 meters. However, reviewing the correct number is needed to solve the equation considering all speed parameters. The
A thief pursued by a policeman was 150 m ahead at the start. If the ratio of the speed of the policeman to that of the thief was 5:4, then how far (distance in metres) could the thief go before he is caught by the policeman?
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