A tap fills a cistern in 14 hours. Another tap empties the full tank in 18 hours. How long (in hours) will it take to fill the tank completely, if the tank is empty and both the taps are open together?
This question involves calculating the combined time taken to fill a cistern when one tap is filling it and another tap is simultaneously emptying it. We need to determine the net rate at which the cistern is filled.
Understanding Tap Rates
First, let's determine the rate at which each tap works. The rate is the portion of the cistern that the tap can fill or empty in one hour.
- Filling Tap Rate: The first tap fills the cistern in 14 hours. So, in 1 hour, it fills $1/14$ of the cistern.
- Emptying Tap Rate: The second tap empties the cistern in 18 hours. So, in 1 hour, it empties $1/18$ of the cistern.
Calculating Net Filling Rate
When both taps are open, the filling tap adds water, and the emptying tap removes water. The net rate of filling is the difference between the filling rate and the emptying rate.
Net Filling Rate = (Rate of Filling Tap) - (Rate of Emptying Tap)
Net Filling Rate = $\frac{1}{14} - \frac{1}{18}$
To subtract these fractions, we find a common denominator. The least common multiple (LCM) of 14 and 18 is 126.
Net Filling Rate = $\frac{1 \times 9}{14 \times 9} - \frac{1 \times 7}{18 \times 7}$
Net Filling Rate = $\frac{9}{126} - \frac{7}{126}$
Net Filling Rate = $\frac{9 - 7}{126}$
Net Filling Rate = $\frac{2}{126}$
Simplifying the fraction:
Net Filling Rate = $\frac{1}{63}$
This means that when both taps are open, $\frac{1}{63}$ of the cistern is filled every hour.
Calculating Total Time to Fill
To find the total time it takes to fill the entire cistern (1 whole cistern), we take the reciprocal of the net filling rate.
Time = $\frac{\text{Total Work}}{\text{Net Filling Rate}}$
Time = $\frac{1}{\frac{1}{63}}$
Time = $63$ hours
Therefore, it will take 63 hours to fill the tank completely when both taps are open.
Important Questions from Pipe and Cistern
Pipes A, B and C can fill a tank in 20, 30 and 60 hours, respectively. Pipes A, B and C are opened at 7 a.m., 8 a.m., and 9 a.m., respectively, on the same day. When will the tank be full?
There are two water taps in a tank which can fill the empty tank in 12 hours and 18 hours respectively. It is seen that there is a leakage point at the bottom of the tank which can empty the completely filled tank in 36 hours. If both the water taps are opened at the same time to fill the empty tank and leakage point was repaired after 1 hour, then in how much time the empty tank will be completely filled?
Two pipes A and B can fill a tank in 12 minutes and 24 minutes, respectively, while a third pipe C can empty the full tank in 32 minutes. All the three pipes are opened simultaneously. However, pipe C is closed 2 minutes before the tank is filled. In how much time (in minutes) will the tank be full?
Pipes A and B can fill a tank in 12 hours and 16 hours respectively and pipe C can empty the full tank in 24 hours. All three pipes are opened together, but after 4 hours pipe B is closed. In how many hours, the empty tank will be completely filled?
Pipes A and B can fill a tank in 43.2 minutes and 108 minutes, respectively. Pipe C can empty it at 3 litres/minute. When all the three pipes are opened together, they fill the tank in 54 minutes. The capacity (in litres) of the tank is:
