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Question

A system has 99.99% uptime and has a mean-time-between-failure of 1 day. How fast does the system has to repair itself in order to reach this availability goal?

The correct answer is

9 Seconds

Calculating System Repair Time for 99.99% Uptime

This question asks us to determine how quickly a system needs to repair itself, given its target availability (uptime) and how often it fails. This involves understanding the key concepts of Availability, Mean Time Between Failure (MTBF), and Mean Time To Repair (MTTR).

Understanding Key Reliability Metrics: Availability, MTBF, and MTTR

  • Availability: This is the percentage of time a system is operational and accessible. An availability of 99.99% means the system is up for a very large portion of the total time.
  • Mean Time Between Failure (MTBF): This is the average time the system operates correctly between failures. A higher MTBF indicates a more reliable system that breaks down less often.
  • Mean Time To Repair (MTTR): This is the average time it takes to fix the system and bring it back online after a failure. A lower MTTR means the system can recover quickly from breakdowns.

These three metrics are related by the following formula for Availability:

$$ \text{Availability} = \frac{\text{MTBF}}{\text{MTBF} + \text{MTTR}} $$

This formula shows that availability increases when the system operates longer between failures (higher MTBF) or when it is repaired faster after a failure (lower MTTR).

Solving for Mean Time To Repair (MTTR)

We are given the Availability and the MTBF and need to find the MTTR. We can rearrange the formula to solve for MTTR.

Starting with the formula:

$$ \text{Availability} = \frac{\text{MTBF}}{\text{MTBF} + \text{MTTR}} $$

Multiply both sides by $ (\text{MTBF} + \text{MTTR}) $:

$$ \text{Availability} \times (\text{MTBF} + \text{MTTR}) = \text{MTBF} $$

Distribute Availability:

$$ (\text{Availability} \times \text{MTBF}) + (\text{Availability} \times \text{MTTR}) = \text{MTBF} $$

Subtract $ (\text{Availability} \times \text{MTBF}) $ from both sides:

$$ \text{Availability} \times \text{MTTR} = \text{MTBF} - (\text{Availability} \times \text{MTBF}) $$

Factor out MTBF on the right side:

$$ \text{Availability} \times \text{MTTR} = \text{MTBF} \times (1 - \text{Availability}) $$

Finally, divide by Availability to find MTTR:

$$ \text{MTTR} = \text{MTBF} \times \left( \frac{1 - \text{Availability}}{\text{Availability}} \right) $$

Alternatively, we could use the derivation shown in the thinking process which is equivalent:

$$ \text{MTTR} = \text{MTBF} \left( \frac{1}{\text{Availability}} - 1 \right) $$

Applying the Values to Calculate MTTR

We are given:

  • Availability = 99.99% = 0.9999
  • MTBF = 1 day

The options for MTTR are in seconds, so we need to convert the MTBF from days to seconds.

  • 1 day = 24 hours
  • 1 hour = 60 minutes
  • 1 minute = 60 seconds

So, MTBF in seconds = $ 1 \text{ day} \times \frac{24 \text{ hours}}{1 \text{ day}} \times \frac{60 \text{ minutes}}{1 \text{ hour}} \times \frac{60 \text{ seconds}}{1 \text{ minute}} $

$$ \text{MTBF} = 1 \times 24 \times 60 \times 60 \text{ seconds} = 86400 \text{ seconds} $$

Now, plug the values into the formula for MTTR:

$$ \text{MTTR} = \text{MTBF} \left( \frac{1}{\text{Availability}} - 1 \right) $$

$$ \text{MTTR} = 86400 \text{ seconds} \times \left( \frac{1}{0.9999} - 1 \right) $$

Calculate the term in the parenthesis:

$$ \frac{1}{0.9999} \approx 1.00010001 $$

$$ \frac{1}{0.9999} - 1 \approx 1.00010001 - 1 = 0.00010001 $$

Now calculate the MTTR:

$$ \text{MTTR} \approx 86400 \text{ seconds} \times 0.00010001 $$

$$ \text{MTTR} \approx 8.640864 \text{ seconds} $$

The calculated Mean Time To Repair is approximately 8.64 seconds.

Comparing Calculation to Options

Let's look at the provided options:

  • 9 Seconds
  • 10 Seconds
  • 11 Seconds
  • 12 Seconds

The calculated MTTR of approximately 8.64 seconds is closest to 9 seconds.

Conclusion

To achieve 99.99% uptime with a Mean Time Between Failure of 1 day, the system needs to have a Mean Time To Repair of approximately 8.64 seconds. Among the given options, 9 seconds is the closest value.

Revision Table: System Availability Calculations

Metric Definition Formula Relationship
Availability Proportion of time a system is functioning $ \frac{\text{MTBF}}{\text{MTBF} + \text{MTTR}} $
Mean Time Between Failure (MTBF) Average time system works before failing Availability $ \times (\text{MTBF} + \text{MTTR}) $
(Derived from Availability formula)
Mean Time To Repair (MTTR) Average time to fix system after failing $ \text{MTBF} \left( \frac{1}{\text{Availability}} - 1 \right) $
(Derived from Availability formula)

Additional Information: System Reliability and Uptime

Achieving high levels of system availability, like 99.99% (often called 'four nines' availability), requires significant effort in system design, monitoring, and maintenance. Even a seemingly small amount of downtime adds up over a year:

  • 99% availability = 3.65 days downtime per year
  • 99.9% availability = 8.76 hours downtime per year
  • 99.99% availability = 52.56 minutes downtime per year
  • 99.999% availability = 5.26 minutes downtime per year ('five nines')

To reach very high availability targets, organizations often focus on both increasing MTBF (making systems more robust and less prone to failure) and decreasing MTTR (having efficient processes and tools for quick detection and repair). Redundancy, automated failover, comprehensive monitoring, and well-practiced recovery procedures are crucial for minimizing MTTR and maximizing availability.

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