Cell Calculation Steps
This problem involves calculating the number of cells after a period of growth and distribution.
1. Initial Cell Distribution:
The initial $1.8 \times 10^5$ monkey kidney cells were seeded into 3 identical flasks. Therefore, the number of cells per flask initially was:
$ \frac{1.8 \times 10^5 \text{ cells}}{3 \text{ flasks}} = 0.6 \times 10^5 \text{ cells/flask} $
2. Cell Growth Calculation:
The doubling time of the cells is 24 hours. The cells were allowed to grow for 24 hours. This means the cell population doubled exactly once.
Number of cells per flask after 24 h:
$ 0.6 \times 10^5 \text{ cells/flask} \times 2 = 1.2 \times 10^5 \text{ cells/flask} $
3. Pooling Cells:
The cells from all three flasks were pooled together.
Total number of cells pooled:
$ 1.2 \times 10^5 \text{ cells/flask} \times 3 \text{ flasks} = 3.6 \times 10^5 \text{ cells} $
4. Dispensing into Plates:
The pooled cells were equally dispensed into each well of three 6-well plates.
Total number of wells:
$ 3 \text{ plates} \times 6 \text{ wells/plate} = 18 \text{ wells} $
5. Cells Per Well Calculation:
Calculate the number of cells in each well by dividing the total pooled cells by the total number of wells.
Number of cells per well:
$ \frac{3.6 \times 10^5 \text{ cells}}{18 \text{ wells}} = 0.2 \times 10^5 \text{ cells/well} $
6. Final Answer Formatting:
Express the result in the format ________ $\times 10^4$.
$ 0.2 \times 10^5 = 0.2 \times 10 \times 10^4 = 2.0 \times 10^4 $
Therefore, the number of cells in each well is 2.0 $\times 10^4$.
Important Questions from Kinetics of Cell Growth
- In the process of generating a clonal mammalian cell line, a single cell was seeded in a well of a cell culture plate. After the first 48 hours, one of the progeny cells underwent apoptosis due to a new mutation. If the doubling time of the cells is 24 hours and no more cell death occurs, the total number of cells after a total of 7 days from seeding will be ______. (answer in integer)
- Maximum specific growth rate ($\mu_{max}$) of a microorganism is calculated by taking the (In=loge, X=biomass, t = time)
- Which one of the following is NOT used for the measurement of cell viability in animal cell culture?
- A T-flask is seeded with $10^5$ anchorage-dependent cells. The available area of the T-flask is $25 \text{ cm}^2$ and the volume of the medium is $25 \text{ ml}$. Assume that the cells are rectangles of size $5 \text{ µm} \times 2 \text{ µm}$. If the cells grow to monolayer confluence after $50 \text{ h}$, the growth rate in number of cells/($\text{cm}^2.\text{h}$) is _________ $ \times 10^5$.
- Determine the correctness or otherwise of the following Assertion (a) and the Reason (r) Assertion: In synchronous culture, majority of the cells move to next phase of the cell cycle simultaneously. Reason: Synchronous culture could be obtained by starving cells for essential nutrient components.
