A sum of Rs. 2000 will become Rs. 2400 in 12 months at some rate of simple interest. Find the rate of interest per annum.
20%
This problem asks us to find the rate of simple interest per annum given a principal amount, the final amount after a certain time period, and the time period itself.
Let's break down the information provided in the question:
Simple interest (I) is the difference between the final amount and the principal amount. The formula is:
\( I = A - P \)
Substituting the given values:
\( I = 2400 - 2000 \)
\( I = 400 \)
So, the simple interest earned is Rs. 400.
The time period is given as 12 months. To use the simple interest formula for a rate per annum, the time must be in years. 12 months is equal to 1 year.
\( T = 12 \text{ months} = 1 \text{ year} \)
The formula for simple interest is:
\( I = \frac{P \times R \times T}{100} \)
Where:
We need to find R. We can rearrange the formula to solve for R:
\( R = \frac{I \times 100}{P \times T} \)
Now, we substitute the values we have:
\( R = \frac{400 \times 100}{2000 \times 1} \)
\( R = \frac{40000}{2000} \)
To simplify, we can cancel out zeros:
\( R = \frac{400}{20} \)
\( R = \frac{40}{2} \)
\( R = 20 \)
The rate of simple interest is 20% per annum.
A sum of Rs. 2000 becomes Rs. 2400 in 12 months at a simple interest rate of 20% per annum.
| Term | Value |
|---|---|
| Principal (P) | Rs. 2000 |
| Amount (A) | Rs. 2400 |
| Time (T) | 1 year |
| Simple Interest (I) | Rs. 400 |
| Rate of Interest (R) | 20% |
Reviewing the key concepts involved in simple interest problems:
It's important to distinguish simple interest from compound interest:
This question specifically dealt with simple interest, making the calculation straightforward based on the initial principal.
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