A sum of money amounts to Rs.1600 in two years and Rs. 1700 in three years, at compounded interest, compounded annually. What is the rate of interest?
6.25%
The question asks us to find the rate of interest when a sum of money grows to a certain amount in two years and another amount in three years, with compound interest compounded annually.
We are given the following information:
In compound interest, the interest for any year is calculated on the amount accumulated till the end of the previous year. Therefore, the interest earned during the third year is calculated on the amount at the end of the second year (A2).
The interest earned during the 3rd year is the difference between the amount after 3 years and the amount after 2 years.
Interest for 3rd year = A3 - A2
Interest for 3rd year = Rs. 1700 - Rs. 1600
Interest for 3rd year = Rs. 100
The interest of Rs. 100 earned in the 3rd year is based on the principal amount at the beginning of the 3rd year, which is Rs. 1600 (the amount after 2 years). We can use the simple interest formula for this specific year to find the rate, as the principal (amount at the end of year 2) remains constant for calculating interest for the next period (year 3).
Let the rate of interest be r% per annum.
Interest = Principal × Rate × Time
Here, Principal = Amount after 2 years = Rs. 1600, Interest = Rs. 100, and Time = 1 year (the 3rd year).
So, we have:
$$100 = 1600 \times \frac{r}{100} \times 1$$
Now, we solve for r:
$$\frac{100}{1600} = \frac{r}{100}$$
Multiply both sides by 100:
$$r = \frac{100}{1600} \times 100$$
$$r = \frac{1}{16} \times 100$$
$$r = \frac{100}{16}$$
$$r = \frac{25}{4}$$
$$r = 6.25$$
Thus, the rate of interest is 6.25% per annum.
The calculated rate of interest is 6.25%.
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