A student has to obtain 33% of the total marks to pass an examination. He got 148 marks and failed by 50 marks. The maximum marks of the examination are:
(d) 600
This problem requires us to find the total maximum marks of an examination given the passing percentage, the marks a student obtained, and the number of marks by which the student failed.
The key insight here is that if the student had obtained 50 more marks, they would have passed the examination. Therefore, the passing marks can be calculated by adding the marks obtained and the marks failed by.
The number of marks required to pass the examination is the sum of the marks the student got and the marks they needed to pass.
Passing Marks $=$ Marks Obtained $+$ Marks Failed By
Passing Marks $=$ $148 + 50$
Passing Marks $=$ $198$ marks
So, the minimum marks required to pass the examination are 198.
We are told that the passing marks are 33% of the total marks. Let's denote the maximum marks (total marks) of the examination as $M$.
According to the problem statement:
33% of Total Marks $=$ Passing Marks
$33\%$ of $M = 198$
We can write 33% as a fraction or a decimal:
$\frac{33}{100} \times M = 198$
Now we need to isolate $M$ in the equation:
$\frac{33}{100} \times M = 198$
To find $M$, we can multiply both sides of the equation by $\frac{100}{33}$:
$M = 198 \times \frac{100}{33}$
We can simplify the calculation by dividing 198 by 33. Let's perform the division:
$198 \div 33$
$33 \times 6 = 198$
So, $198/33 = 6$.
Now substitute this back into the equation for $M$:
$M = 6 \times 100$
$M = 600$
Therefore, the maximum marks for the examination are 600.
Let's check if 33% of 600 is indeed 198.
$33\%$ of $600 = \frac{33}{100} \times 600 = 33 \times 6 = 198$
The passing marks are 198. The student got 148 marks, which is $198 - 148 = 50$ marks less than the passing marks. This matches the information given that the student failed by 50 marks.
The calculations are consistent with the problem statement.
The maximum marks of the examination are 600.
| Concept | Description | Formula/Method |
|---|---|---|
| Passing Marks | Minimum marks required to pass the exam. | Marks Obtained + Marks Failed By |
| Passing Percentage | Passing marks expressed as a percentage of total marks. | (Passing Marks / Total Marks) * 100% |
| Total Marks (Maximum Marks) | The highest possible score in the exam. | (Passing Marks / Passing Percentage) * 100 |
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