A step-up chopper is supplied through a source of 200 V and operated at a duty cycle of 50%. Find the average output voltage of the chopper.
A step-up chopper, also known as a boost chopper, is a power electronic converter that produces an output voltage greater than its input DC voltage. It achieves this voltage step-up by rapidly switching a semiconductor device (like a MOSFET or IGBT) to store energy in an inductor and then release it to the load at a higher voltage.
The operation of a step-up chopper relies on the energy stored in an inductor. When the switch is ON, the inductor stores energy from the source. When the switch is OFF, the inductor's polarity reverses, and its stored energy adds to the source voltage, resulting in a higher output voltage across the load. The amount of voltage step-up is controlled by the duty cycle of the chopper.
The average output voltage (\(V_o\)) of a step-up chopper is determined by the input source voltage (\(V_s\)) and the duty cycle (\(\alpha\)). The formula for the average output voltage of a step-up chopper is:
\[V_o = \frac{V_s}{1 - \alpha}\]Where:
From the problem statement, we have the following values:
To find the average output voltage of the step-up chopper, we will follow these steps:
Based on the calculations, the average output voltage of the step-up chopper is 400 V.
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