A steel wheel of 600 mm diameter rolls on a horizontal steel rail. It carries a load of 500 N. The coefficient of rolling resistance is 0.3 mm. The force in N, necessary to roll the wheel along the rail is:
0.5
This question involves calculating the force required to overcome rolling resistance when a steel wheel rolls on a horizontal steel rail. Rolling resistance is a force that resists the motion when a body (like a wheel) rolls on a surface. It's caused by factors like deformation of the wheel and the surface.
We are provided with the following information:
The radius ($R$) of the wheel is half of its diameter ($D$).
The formula is: $R = \frac{D}{2}$
Substituting the given diameter:
$R = \frac{600 \, \text{mm}}{2}$
$R = 300 \, \text{mm}$
The force ($F$) required to overcome rolling resistance is calculated using the coefficient of rolling resistance ($a$), the load ($W$), and the wheel radius ($R$). The formula used when the coefficient is given in units of length (like mm) is:
$$ F = W \times \frac{a}{R} $$
Where:
It's important that the units for '$a$' and '$R$' are consistent (both in mm in this case).
Now, let's substitute the known values into the formula:
$$ F = 500 \, \text{N} \times \frac{0.3 \, \text{mm}}{300 \, \text{mm}} $$
First, calculate the ratio $\frac{a}{R}$:
$$ \frac{0.3}{300} = 0.001 $$
Now, multiply this ratio by the load ($W$):
$$ F = 500 \, \text{N} \times 0.001 $$
$$ F = 0.5 \, \text{N} $$
The calculated force necessary to roll the wheel along the rail is 0.5 N. This matches the first option provided.
The maximum static frictional force that an object experiences just before it begins to slide over a surface is commonly referred to as the:
Coefficient of friction depends upon
Limiting force of friction is the
Coulomb friction is the friction between
The minimum angle made by an inclined plane with the horizontal such that an object placed on the inclined surface just begins to slide is called-