A stationary CW radar operating at 5 GHz. What is the Doppler frequency shift, if the target is moving at 108 km/hr speed?
1000 Hz
The Doppler frequency shift is a fundamental concept in radar systems, especially for Continuous Wave (CW) radar. It refers to the change in the frequency of a wave due to the relative motion between the source (radar) and the observer (target). When a CW radar transmits an electromagnetic wave towards a moving target, the wave reflected back to the radar experiences a frequency shift. This shift, known as the Doppler frequency shift, is directly proportional to the target's speed and helps in determining how fast the target is moving.
To calculate the Doppler frequency shift, we first need to list the information provided in the question:
| Parameter | Value | Units |
|---|---|---|
| Radar Frequency ($\text{f}_\text{c}$) | 5 | GHz |
| Target Speed ($\text{v}$) | 108 | km/hr |
| Speed of Light ($\text{c}$) | $3 \times 10^8$ | m/s |
For accurate calculations using the Doppler frequency shift formula, it is essential to convert all given units into a consistent system, typically the International System of Units (SI units).
We know that $1 \text{ GHz} = 10^9 \text{ Hz}$.
Therefore, the radar operating frequency is: $\text{f}_\text{c} = 5 \text{ GHz} = 5 \times 10^9 \text{ Hz}$.
We know that $1 \text{ km} = 1000 \text{ m}$ and $1 \text{ hour} = 3600 \text{ seconds}$.
So, the target speed is: $\text{v} = 108 \text{ km/hr} = 108 \times \frac{1000 \text{ m}}{3600 \text{ s}}$.
$\text{v} = 108 \times \frac{10}{36} \text{ m/s} = 3 \times 10 \text{ m/s} = 30 \text{ m/s}$.
For a stationary CW radar and a target moving directly towards or away from it, the Doppler frequency shift ($\text{f}_\text{d}$) is calculated using the following formula:
$$ \text{f}_\text{d} = \frac{2 \times \text{v} \times \text{f}_\text{c}}{\text{c}} $$
Where:
Now, let's substitute the converted values into the Doppler frequency shift formula:
$$ \text{f}_\text{d} = \frac{2 \times (30 \text{ m/s}) \times (5 \times 10^9 \text{ Hz})}{3 \times 10^8 \text{ m/s}} $$
First, multiply the terms in the numerator:
$$ 2 \times 30 \times 5 \times 10^9 = 300 \times 10^9 $$
Now, substitute this back into the formula:
$$ \text{f}_\text{d} = \frac{300 \times 10^9}{3 \times 10^8} \text{ Hz} $$
Divide the numerical parts and subtract the exponents:
$$ \text{f}_\text{d} = \left(\frac{300}{3}\right) \times 10^{(9-8)} \text{ Hz} $$
$$ \text{f}_\text{d} = 100 \times 10^1 \text{ Hz} $$
$$ \text{f}_\text{d} = 1000 \text{ Hz} $$
So, the Doppler frequency shift is 1000 Hz.
After calculating the Doppler frequency shift, we compare the result with the given options:
The calculated Doppler frequency shift of 1000 Hz perfectly matches Option 2.
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