A square pyramid has a base perimeter x, and the slant height is half of the perimeter. What is the lateral surface area of the pyramid?
0.25x2
Understanding the properties of a square pyramid is crucial for calculating its lateral surface area. A square pyramid is a three-dimensional geometric shape with a square base and four triangular faces that meet at a single point (apex).
The problem provides us with two key pieces of information about the pyramid:
First, we need to determine the side length of the square base. For a square, all four sides are equal in length. The perimeter of a square is the sum of its four sides.
Let $a$ be the side length of the square base.
Given: Perimeter $= x$
Formula for perimeter of a square: $\text{Perimeter} = 4 \times \text{side}$
So, $x = 4a$
To find the side length, divide the perimeter by 4:
$a = \frac{x}{4}$
The lateral surface area of a pyramid is the sum of the areas of all its triangular faces. For a square pyramid, there are four identical triangular faces. The area of one such triangular face is calculated using the formula for the area of a triangle: $\frac{1}{2} \times \text{base} \times \text{height}$.
In this context:
The area of one triangular face $= \frac{1}{2} \times a \times l$.
Since there are four such faces, the total lateral surface area (LSA) of the square pyramid is:
$\text{LSA} = 4 \times \left(\frac{1}{2} \times a \times l\right)$
$\text{LSA} = 2 \times a \times l$
Now, we substitute the values we have found for the side length $a$ and the given slant height $l$ into the lateral surface area formula.
Substitute these values into the formula for lateral surface area:
$\text{LSA} = 2 \times \left(\frac{x}{4}\right) \times \left(\frac{x}{2}\right)$
Multiply the terms:
$\text{LSA} = 2 \times \frac{x \times x}{4 \times 2}$
$\text{LSA} = 2 \times \frac{x^2}{8}$
Simplify the expression by dividing the numerator and denominator by 2:
$\text{LSA} = \frac{x^2}{4}$
To express this as a decimal, we convert the fraction:
$\text{LSA} = 0.25x^2$
The lateral surface area of the square pyramid, given its base perimeter $x$ and slant height as half the perimeter, is $0.25x^2$.
| Property | Value |
|---|---|
| Base Perimeter | $x$ |
| Side Length of Base ($a$) | $\frac{x}{4}$ |
| Slant Height ($l$) | $\frac{x}{2}$ |
| Lateral Surface Area (LSA) | $0.25x^2$ |
This result matches option 4.
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