We need to estimate the number of picks per centimeter for a square plain woven fabric with a thickness of 0.5 mm made from polyester yarns, assuming a circular yarn cross-section.
In a plain weave, the fabric thickness (T) is approximately the sum of the warp yarn diameter (d) and the weft yarn diameter (d). Since the yarn is assumed to be uniform:
$ T \approx d + d = 2d $
Given T = 0.5 mm, we can find the yarn diameter:
$ d \approx \frac{T}{2} = \frac{0.5 \text{ mm}}{2} = 0.25 \text{ mm} $
The number of yarns per unit length (density, N) is related to the yarn diameter (d). A common approximation uses the concept of cover factor ($k_c$), which represents the fraction of area covered by warp or weft yarns. For plain weave, the cover factor is roughly 0.5.
$ k_c \approx N \times d $
Rearranging to find N:
$ N \approx \frac{k_c}{d} $
First, convert the yarn diameter to centimeters:
$ d = 0.25 \text{ mm} = 0.025 \text{ cm} $
Now, calculate N using the approximate cover factor ($k_c \approx 0.5$):
$ N \approx \frac{0.5}{0.025 \text{ cm}} = 20 \text{ picks/cm} $
The calculated approximate value is 20 picks per cm. Comparing this to the given options:
The value 20 is closest to the option 23. The difference can be attributed to the simplified assumptions used (perfect circles, constant packing, idealized plain weave, and approximate cover factor).
A series of plain knitted fabrics has varying stitch length ($\ell $). The fabrics are composed of cotton yarns having same packing density but differing in linear density ($T$). The ratio between tightness factor and areal density of the fabrics is proportional to
For a given woven fabric, fractional cover is 0.5 for both warp and weft. The fractional cover of the fabric, (rounded off to two decimal places), is____.
Cloth cover factor of a square plain jammed cotton fabric, accurate to one decimal place, is________.