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Question

A sphere has a surface area of 400 π mm2. What is the diameter?

The correct answer is

20 mm

Sphere Surface Area to Diameter Calculation

The question asks us to find the diameter of a sphere when its surface area is given as $400\pi$ mm$^2$. We need to use the formula for the surface area of a sphere and the relationship between radius and diameter.

Sphere Formulas

The key formulas needed are:

  • Surface Area of a sphere ($A$): $A = 4\pi r^2$, where $r$ is the radius.
  • Diameter of a sphere ($d$): $d = 2r$.

Calculating the Sphere's Radius

We are given the surface area $A = 400\pi$ mm$^2$. We can use the surface area formula to find the radius ($r$).

  1. Start with the surface area formula:

    $A = 4\pi r^2$

  2. Substitute the given surface area value into the formula:

    $400\pi = 4\pi r^2$

  3. To solve for $r^2$, divide both sides of the equation by $4\pi$:

    $r^2 = \frac{400\pi}{4\pi}$

    $r^2 = 100$

  4. Now, find the radius ($r$) by taking the square root of $r^2$:

    $r = \sqrt{100}$

    $r = 10$ mm

Determining the Sphere's Diameter

Once we have the radius, we can easily calculate the diameter using the formula $d = 2r$.

  1. Use the diameter formula:

    $d = 2r$

  2. Substitute the calculated radius ($r = 10$ mm):

    $d = 2 \times 10$ mm

    $d = 20$ mm

So, the diameter of the sphere is 20 mm. This matches the second option provided.

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Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

  2. A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:

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  4. Consider the following statements:

    1. Distance between the longitudes becomes zero on North Pole and South Pole.

    2. Distance between the longitudes is maximum on the Equator.

    3. Number of longitudes is more than number of latitudes.

    Which of the statements given above is/are correct?

  5. One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :

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