A soil sample is subjected to a hydrostatic pressure σ. The Mohr circle for any point in the soil sample would be
A point at a distance σ from the origin
When a soil sample is subjected to hydrostatic pressure, it means that the pressure acting on the soil is uniform and equal in all directions. Imagine the soil being completely submerged in a fluid; the pressure at any point within the fluid at a certain depth is equal in all directions. In terms of stress, this implies a very specific stress state within the soil sample.
In a state of hydrostatic pressure \(\sigma\), the normal stresses acting on any plane passing through a point are equal in magnitude, and importantly, the shear stresses on these planes are zero. This is a crucial characteristic. Mathematically, we can express the normal stresses along the principal axes as:
\[ \sigma_x = \sigma_y = \sigma_z = \sigma \]
And the shear stresses in all directions are zero:
\[ \tau_{xy} = \tau_{yz} = \tau_{zx} = 0 \]
Since the shear stresses are zero on all planes, it means that every plane is a principal plane, and the normal stresses are the principal stresses.
The Mohr circle is a graphical tool used in geotechnical engineering to represent the state of stress at a point within a material. It plots normal stress (\(\sigma\)) on the x-axis and shear stress (\(\tau\)) on the y-axis.
For a two-dimensional stress state, the center and radius of the Mohr circle are determined by the principal stresses. In a three-dimensional case, we typically consider the largest and smallest principal stresses to define the main Mohr circle for analysis, or we consider circles for different planes (e.g., \(\sigma_1\) and \(\sigma_3\)).
Here, \(\sigma_1\) is the major principal stress and \(\sigma_3\) is the minor principal stress. In a hydrostatic condition, all principal stresses are equal.
Given that the soil sample is under hydrostatic pressure \(\sigma\), all principal stresses are equal to \(\sigma\). So, we have:
Now, let's calculate the center and radius of the Mohr circle:
A Mohr circle with a radius of zero means that the circle degenerates into a single point. This point is located on the normal stress (\(\sigma\)) axis at a distance equal to the center of the circle from the origin.
The coordinates of this point would be \((\sigma, 0)\).
This single point graphically represents that for any orientation of a plane through the point in the soil sample, the normal stress will always be \(\sigma\), and the shear stress will always be zero.
| Stress Parameter | Value under Hydrostatic Pressure \(\sigma\) |
|---|---|
| Principal Stresses (\(\sigma_1, \sigma_2, \sigma_3\)) | \(\sigma\) |
| Shear Stresses (\(\tau_{xy}, \tau_{yz}, \tau_{zx}\)) | 0 |
| Mohr Circle Center (C) | \(\sigma\) |
| Mohr Circle Radius (R) | 0 |
| Mohr Circle Representation | A Point |
Therefore, the Mohr circle for any point in the soil sample subjected to a hydrostatic pressure \(\sigma\) is a point at a distance \(\sigma\) from the origin on the normal stress axis.
In a direct shear test, the soil load is subjected to more stress at the _______.
The expansion of soil due to shear at a constant value of pressure is called
In the triaxial compression test, the application of additional axial stress on the soil specimen produces shear stress on:
The angle of the failure plane with the major principal plane is given by
The length of the specimen in a triaxial test is kept about _____ times its diameter.