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Question

A single phase energy meter is operating on 230 V, 50 Hz supply with a load of 20 A for two hours at UPF. The meter makes 1380 revolutions in that period. The meter constant is

The correct answer is

150 rev/kWh

Energy Meter Operation Details

This solution explains how to calculate the meter constant for a single-phase energy meter based on its operating conditions and performance. The meter constant, typically expressed in revolutions per kilowatt-hour (rev/kWh), indicates how many times the meter's disc rotates to measure one unit of energy.

Electrical Parameters for Calculation

To determine the energy meter constant, we need to consider the electrical parameters provided:

  • Supply Voltage ($V$): 230 V
  • Load Current ($I$): 20 A
  • Power Factor ($\cos \phi$): 1 (Unity Power Factor - UPF)
  • Time Duration ($t$): 2 hours
  • Observed Revolutions ($N$): 1380 revolutions

Meter Constant Calculation Steps

The calculation involves determining the total energy consumed and then relating it to the number of revolutions the meter disc made.

  1. Calculate Real Power (P):

    The real power consumed by the load is calculated using the formula for a single-phase circuit:

    $$ P = V \times I \times \cos \phi $$

    Substituting the given values:

    $$ P = 230 \, \text{V} \times 20 \, \text{A} \times 1 $$

    $$ P = 4600 \, \text{W} $$

  2. Convert Power to Kilowatts (kW):

    Energy is measured in kilowatt-hours (kWh), so we convert the power from Watts (W) to kilowatts (kW):

    $$ P_{\text{kW}} = \frac{P_{\text{W}}}{1000} $$

    $$ P_{\text{kW}} = \frac{4600 \, \text{W}}{1000} $$

    $$ P_{\text{kW}} = 4.6 \, \text{kW} $$

  3. Calculate Energy Consumed (E):

    The total energy consumed over the specified time duration is calculated as:

    $$ E = P_{\text{kW}} \times t $$

    Using the calculated power and the given time:

    $$ E = 4.6 \, \text{kW} \times 2 \, \text{h} $$

    $$ E = 9.2 \, \text{kWh} $$

  4. Calculate Meter Constant (K):

    The meter constant ($K$) is defined as the ratio of the number of revolutions to the energy consumed in kWh:

    $$ K = \frac{\text{Total Revolutions}}{\text{Energy Consumed}} $$

    $$ K = \frac{N}{E} $$

    Plugging in the values:

    $$ K = \frac{1380 \, \text{rev}}{9.2 \, \text{kWh}} $$

    To simplify the division:

    $$ K = \frac{13800}{92} \, \text{rev/kWh} $$

    $$ K = 150 \, \text{rev/kWh} $$

Calculated Meter Constant Result

Based on the calculations, the meter constant for the single-phase energy meter under the given load conditions is 150 rev/kWh.

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Important Questions from Induction Type Energy Meter

  1. The cores of electromagnets used in energy meter are made up of

  2. Which of the following statements best describes a primary benefit of using phantom loading for the calibration and testing of energy meters?

  3. The speed of the aluminum disc in an energy meter is controlled by __________.

  4. Creep adjustments in single-phase energy metres are done by _______.

  5. The compensation for light load is done by using a metallic strip provided between the ________.

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