A single phase energy meter is operating on 230 V, 50 Hz supply with a load of 20 A for two hours at UPF. The meter makes 1380 revolutions in that period. The meter constant is
150 rev/kWh
This solution explains how to calculate the meter constant for a single-phase energy meter based on its operating conditions and performance. The meter constant, typically expressed in revolutions per kilowatt-hour (rev/kWh), indicates how many times the meter's disc rotates to measure one unit of energy.
To determine the energy meter constant, we need to consider the electrical parameters provided:
The calculation involves determining the total energy consumed and then relating it to the number of revolutions the meter disc made.
The real power consumed by the load is calculated using the formula for a single-phase circuit:
$$ P = V \times I \times \cos \phi $$
Substituting the given values:
$$ P = 230 \, \text{V} \times 20 \, \text{A} \times 1 $$
$$ P = 4600 \, \text{W} $$
Energy is measured in kilowatt-hours (kWh), so we convert the power from Watts (W) to kilowatts (kW):
$$ P_{\text{kW}} = \frac{P_{\text{W}}}{1000} $$
$$ P_{\text{kW}} = \frac{4600 \, \text{W}}{1000} $$
$$ P_{\text{kW}} = 4.6 \, \text{kW} $$
The total energy consumed over the specified time duration is calculated as:
$$ E = P_{\text{kW}} \times t $$
Using the calculated power and the given time:
$$ E = 4.6 \, \text{kW} \times 2 \, \text{h} $$
$$ E = 9.2 \, \text{kWh} $$
The meter constant ($K$) is defined as the ratio of the number of revolutions to the energy consumed in kWh:
$$ K = \frac{\text{Total Revolutions}}{\text{Energy Consumed}} $$
$$ K = \frac{N}{E} $$
Plugging in the values:
$$ K = \frac{1380 \, \text{rev}}{9.2 \, \text{kWh}} $$
To simplify the division:
$$ K = \frac{13800}{92} \, \text{rev/kWh} $$
$$ K = 150 \, \text{rev/kWh} $$
Based on the calculations, the meter constant for the single-phase energy meter under the given load conditions is 150 rev/kWh.
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