A single-cylinder diesel engine has a compression ratio of 16. If the stroke volume during operation is 450 cc, then its clearance volume is
30 cc
To effectively solve this problem, it's essential to understand the key terms related to an internal combustion engine's cylinder volumes:
The compression ratio \(r\) for an internal combustion engine is mathematically expressed as:
\[r = \frac{\text{Total Volume}}{\text{Clearance Volume}} = \frac{V_t}{V_c}\]
Since the total volume \(V_t\) is the sum of the stroke volume \(V_s\) and the clearance volume \(V_c\), we can substitute this into the formula:
\[r = \frac{V_s + V_c}{V_c}\]
This formula can also be rearranged as:
\[r = \frac{V_s}{V_c} + \frac{V_c}{V_c}\]
\[r = 1 + \frac{V_s}{V_c}\]
Now, let's plug in the given values from the problem statement:
Using the derived formula \(r = 1 + \frac{V_s}{V_c}\):
Step 1: Substitute the given values into the formula.
\[16 = 1 + \frac{450 \text{ cc}}{V_c}\]
Step 2: Subtract 1 from both sides of the equation.
\[16 - 1 = \frac{450 \text{ cc}}{V_c}\]
\[15 = \frac{450 \text{ cc}}{V_c}\]
Step 3: Rearrange the equation to solve for \(V_c\).
\[V_c = \frac{450 \text{ cc}}{15}\]
Step 4: Perform the division.
\[V_c = 30 \text{ cc}\]
Therefore, the clearance volume of the single-cylinder diesel engine is 30 cc.
Which of the following medium is compressed in a diesel engine?
For an air-standard Diesel cycle,
For the same maximum pressure and peak temperature, which cycle will be most efficient?
A diesel engine has a compression ratio of 18 and cut off takes place at 5% of the stroke. What will be cut off ratio?