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Question

A shopkeeper professes to sell his goods at a 60% loss but uses a false balance and gains 70%. The actual weight (rounded off to one decimal place) that he uses instead of 1 kg is:

The correct answer is
235.3 gm

Shopkeeper False Balance Problem: Actual Weight Calculation

This solution explains how to find the actual weight used by a shopkeeper who claims a loss but makes a profit using a false balance.

Understanding the Problem

A shopkeeper claims to sell goods at a 60% loss. However, by using a false balance, he actually gains 70%. We need to determine the actual weight used instead of 1 kg.

Key Concepts

  • Marked Price (MP): The price the shopkeeper declares per unit weight.
  • Cost Price (CP): The actual cost price per unit weight for the shopkeeper.
  • False Balance: Used to provide less weight than stated.
  • Gain/Loss Calculation: Gain/Loss % is calculated on the actual cost price.

Step-by-Step Solution

  1. Define Variables and Relationships:

    • Let the cost price (CP) of 1 kg of goods be $C$.
    • Let the marked price (MP) declared by the shopkeeper be $M$.
    • The shopkeeper claims a 60% loss. Therefore, the marked price is:

      $M = C \times (1 - \frac{60}{100}) = C \times (1 - 0.60) = 0.40C$

    • Let $w$ be the actual weight (in kg) used instead of 1 kg.
  2. Calculate Actual Cost Price and Selling Price:

    • The actual cost price for the goods supplied is the cost of $w$ kg:

      Actual CP = $C \times w$

    • The selling price (SP) is the amount received for $w$ kg. Since he uses a false balance, he charges the price equivalent to 1 kg at his marked rate ($M$).

      Selling Price (SP) = $M \times 1 = M$

  3. Apply the Actual Gain Percentage:

    • The shopkeeper gains 70% overall. The formula for gain percentage is:

      Gain % = $ \frac{SP - \text{Actual CP}}{\text{Actual CP}} \times 100 $

    • Substitute the values:

      $70 = \frac{M - (C \times w)}{C \times w} \times 100$

    • Simplify the equation:

      $\frac{70}{100} = \frac{M - Cw}{Cw}$

      $0.70 = \frac{M}{Cw} - 1$

      $1.70 = \frac{M}{Cw}$

      $1.70 Cw = M$

  4. Solve for the Actual Weight ($w$):

    • Substitute $M = 0.40C$ into the equation $1.70 Cw = M$:

      $1.70 Cw = 0.40 C$

    • Divide both sides by $C$ (since $C \neq 0$):

      $1.70 w = 0.40$

    • Solve for $w$:

      $w = \frac{0.40}{1.70} = \frac{4}{17}$ kg

  5. Convert Weight to Grams and Round:

    • To convert kg to grams, multiply by 1000:

      Actual Weight (grams) = $ \frac{4}{17} \times 1000 = \frac{4000}{17} $ grams

    • Calculate the value and round to one decimal place:

      $ \frac{4000}{17} \approx 235.294... $ grams

      Rounded weight = 235.3 gm

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Important Questions from Dishonest Dealings

  1. A trader claims to sell pulses at a profit of 3%, but also dishonestly uses a weight which is 15% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)
  2. A trader claims to sell vegetables at a profit of 52%, but also dishonestly uses a weight which is 8% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)
  3. A trader claims to sell fruits at a profit of 22%, but also dishonestly uses a weight which is 4% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)

  4. A trader claims to sell pulses at a profit of 48%, but also dishonestly uses a weight which is 12% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)
  5. A shopkeeper professes to sell his goods at a 20% loss but uses a false balance and gains 40%. The actual weight (rounded off to one decimal place) he uses for 1 kg is:
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