This solution explains how to find the actual weight used by a shopkeeper who claims a loss but makes a profit using a false balance.
A shopkeeper claims to sell goods at a 60% loss. However, by using a false balance, he actually gains 70%. We need to determine the actual weight used instead of 1 kg.
Define Variables and Relationships:
$M = C \times (1 - \frac{60}{100}) = C \times (1 - 0.60) = 0.40C$
Calculate Actual Cost Price and Selling Price:
Actual CP = $C \times w$
Selling Price (SP) = $M \times 1 = M$
Apply the Actual Gain Percentage:
Gain % = $ \frac{SP - \text{Actual CP}}{\text{Actual CP}} \times 100 $
$70 = \frac{M - (C \times w)}{C \times w} \times 100$
$\frac{70}{100} = \frac{M - Cw}{Cw}$
$0.70 = \frac{M}{Cw} - 1$
$1.70 = \frac{M}{Cw}$
$1.70 Cw = M$
Solve for the Actual Weight ($w$):
$1.70 Cw = 0.40 C$
$1.70 w = 0.40$
$w = \frac{0.40}{1.70} = \frac{4}{17}$ kg
Convert Weight to Grams and Round:
Actual Weight (grams) = $ \frac{4}{17} \times 1000 = \frac{4000}{17} $ grams
$ \frac{4000}{17} \approx 235.294... $ grams
Rounded weight = 235.3 gm
A trader claims to sell fruits at a profit of 22%, but also dishonestly uses a weight which is 4% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)