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Question

A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.

PQSS, SKBG, VEKU, YYTI, ?

The correct answer is BSCW

Letter Series Pattern Analysis

We are given a letter series with one term missing: PQSS, SKBG, VEKU, YYTI, ?. We need to identify the pattern connecting the terms and find the next term in the sequence.

To solve letter series problems, we often look at the alphabetical position of each letter. Let's assign a numerical value to each letter, where A=1, B=2, ..., Z=26.

Term1st Letter2nd Letter3rd Letter4th Letter
PQSSP (16)Q (17)S (19)S (19)
SKBGS (19)K (11)B (2)G (7)
VEKUV (22)E (5)K (11)U (21)
YYTIY (25)Y (25)T (20)I (9)
?????

Identifying Letter Patterns in the Series

Let's examine the pattern for each letter position independently.

First Letter Pattern

The first letters of the terms are P, S, V, Y. Their numerical positions are 16, 19, 22, 25.

Let's find the difference between consecutive terms:

  • From P (16) to S (19): ${19 - 16 = 3}$
  • From S (19) to V (22): ${22 - 19 = 3}$
  • From V (22) to Y (25): ${25 - 22 = 3}$

The pattern for the first letter is adding 3 to the previous letter's position. We work modulo 26, meaning after Z (26), we loop back to A (1).

To find the first letter of the next term, we add 3 to the position of Y (25): ${25 + 3 = 28}$.

Since there are 26 letters, ${28 - 26 = 2}$. The letter at position 2 is B.

The first letter of the next term is B.

Second Letter Pattern

The second letters are Q, K, E, Y. Their numerical positions are 17, 11, 5, 25.

Let's find the difference between consecutive terms, considering the alphabet wraps around:

  • From Q (17) to K (11): ${11 - 17 = -6}$. This is a subtraction of 6.
  • From K (11) to E (5): ${5 - 11 = -6}$. This is a subtraction of 6.
  • From E (5) to Y (25): Moving from 5 back 6 steps: 5→4(D)→3(C)→2(B)→1(A)→26(Z)→25(Y). This is a subtraction of 6. Or numerically: ${5 - 6 = -1}$. Modulo 26, ${-1 \pmod{26} = 25}$, which is Y.

The pattern for the second letter is subtracting 6 from the previous letter's position (modulo 26).

To find the second letter of the next term, we subtract 6 from the position of Y (25): ${25 - 6 = 19}$.

The letter at position 19 is S.

The second letter of the next term is S.

Third Letter Pattern

The third letters are S, B, K, T. Their numerical positions are 19, 2, 11, 20.

Let's find the difference between consecutive terms, considering the alphabet wraps around:

  • From S (19) to B (2): Moving from 19 forward to 2 involves passing Z. ${19 + \text{difference} = 2 + 26k}$. ${2 - 19 = -17}$. Modulo 26, ${-17 \pmod{26} = 9}$. This is an addition of 9. (${19 + 9 = 28}$, ${28 - 26 = 2}$, which is B).
  • From B (2) to K (11): ${11 - 2 = 9}$. This is an addition of 9.
  • From K (11) to T (20): ${20 - 11 = 9}$. This is an addition of 9.

The pattern for the third letter is adding 9 to the previous letter's position (modulo 26).

To find the third letter of the next term, we add 9 to the position of T (20): ${20 + 9 = 29}$.

Modulo 26, ${29 \pmod{26} = 3}$. The letter at position 3 is C.

The third letter of the next term is C.

Fourth Letter Pattern

The fourth letters are S, G, U, I. Their numerical positions are 19, 7, 21, 9.

Let's find the difference between consecutive terms, considering the alphabet wraps around:

  • From S (19) to G (7): Moving from 19 forward to 7 involves passing Z. ${7 - 19 = -12}$. Modulo 26, ${-12 \pmod{26} = 14}$. This is an addition of 14. (${19 + 14 = 33}$, ${33 - 26 = 7}$, which is G).
  • From G (7) to U (21): ${21 - 7 = 14}$. This is an addition of 14.
  • From U (21) to I (9): Moving from 21 forward to 9 involves passing Z. ${9 - 21 = -12}$. Modulo 26, ${-12 \pmod{26} = 14}$. This is an addition of 14. (${21 + 14 = 35}$, ${35 - 26 = 9}$, which is I).

The pattern for the fourth letter is adding 14 to the previous letter's position (modulo 26).

To find the fourth letter of the next term, we add 14 to the position of I (9): ${9 + 14 = 23}$.

The letter at position 23 is W.

The fourth letter of the next term is W.

Completing the Letter Series

By combining the letters found for each position, we get the next term in the series:

  • First letter: B
  • Second letter: S
  • Third letter: C
  • Fourth letter: W

The next term in the series is BSCW.

Revision Table: Letter Series Patterns Summary

Letter PositionSequencePattern (Add/Subtract)Calculation for Next TermNext Letter
1stP, S, V, Y+3Position of Y (25) + 3 = 28 → B (2)B
2ndQ, K, E, Y-6Position of Y (25) - 6 = 19 → S (19)S
3rdS, B, K, T+9Position of T (20) + 9 = 29 → C (3)C
4thS, G, U, I+14Position of I (9) + 14 = 23 → W (23)W

Additional Information: Solving Letter Series Questions

Letter series problems are a common type of question in reasoning and aptitude tests. They require you to find the underlying rule or pattern governing the sequence of letters or groups of letters.

Strategies for solving letter series:

  • Write down the alphabetical position of each letter.
  • Look for differences or relationships between the numerical positions of consecutive letters in each position.
  • Consider patterns like constant addition/subtraction, increasing/decreasing differences, or alternating operations.
  • Remember that the alphabet wraps around (A follows Z). Modulo 26 arithmetic is often useful.
  • Check if there are patterns involving skipping letters or reversals.

Practice with various types of letter series helps in quickly recognizing common patterns.

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Important Questions from Alphabet Series

  1. Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.

    KMTC, EVOM, OQXG, IZSQ, ?

  2. Select the set of letters that when sequentially placed in the blanks of the given letter series will complete the series.

    k_lmml_mk_mmk_lkkl_m
  3. Select the letter will replace the question mark (?) in the following series.

    C, B, B, C, Z, E, W, H, S, ?, N
  4. Which letter will replace the question mark (?) in the following letter series?

    E, J, N, Q, S, ?

  5. Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
    C _ B N _ _ V_ _ H C _ B _ H

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