A runway is being constructed in a new airport as per the International Civil Aviation Organization (ICAO) recommendations. The elevation and the airport reference temperature of the airport are 535 m above the mean sea level and 22.65°C, respectively. Consider the effective gradient of runway as 1%. The length of runway required for a design-aircraft under the standard condition is 2000 m. Within the framework of applying sequential corrections as per the ICAO recommendations, the length of runway corrected for the temperature is
2500 m
The International Civil Aviation Organization (ICAO) provides specific recommendations for calculating the required runway length for airport design. These recommendations involve applying sequential corrections to the basic runway length for various factors like elevation, temperature, and effective gradient. This solution focuses on applying the corrections for elevation and temperature as per the question's requirement.
According to ICAO, the basic runway length needs to be adjusted based on the specific atmospheric and topographical conditions of the airport. These adjustments are applied in a particular sequence:
Let's list the given parameters for our calculation:
| Parameter | Value |
|---|---|
| Length of runway under standard condition ($L_0$) | $2000 \\text{ m}$ |
| Airport Elevation ($E$) | $535 \\text{ m}$ above MSL |
| Airport Reference Temperature (ART or $T_a$) | $22.65^\circ \\text{C}$ |
| Effective Gradient of runway ($G$) | $1\\%$ (Not used for this question's scope) |
The first step in calculating the corrected runway length is to adjust it for the airport's elevation. Air density decreases with altitude, which affects aircraft performance, requiring a longer runway.
First, we need to determine the standard atmospheric temperature at the airport's elevation. The standard temperature at Mean Sea Level (MSL) is $15^\circ \\text{C}$, and the standard temperature lapse rate is $6.5^\circ \\text{C}$ per $1000 \\text{ m}$ elevation rise.
Standard temperature at elevation ($T_s$) is calculated as:
$T_s = \\text{Standard Temperature at MSL} - \\left(\\text{Lapse Rate} \\times \\frac{\\text{Elevation}}{1000}\\right)$
Substituting the values:
$T_s = 15^\circ \\text{C} - \\left(6.5^\circ \\text{C/1000 m} \\times \\frac{535 \\text{ m}}{1000 \\text{ m}}\\right)$
$T_s = 15^\circ \\text{C} - \\left(6.5 \\times 0.535\\right)^\circ \\text{C}$
$T_s = 15^\circ \\text{C} - 3.4775^\circ \\text{C}$
$T_s = 11.5225^\circ \\text{C}$
ICAO recommends an increase in runway length by $7\\%$ for every $300 \\text{ m}$ rise in elevation above mean sea level.
The formula for runway length corrected for elevation ($L_E$) is:
$L_E = L_0 \\times \\left(1 + \\frac{7}{100} \\times \\frac{E}{300}\\right)$
Substituting the values:
$L_E = 2000 \\text{ m} \\times \\left(1 + \\frac{7}{100} \\times \\frac{535 \\text{ m}}{300 \\text{ m}}\\right)$
$L_E = 2000 \\times \\left(1 + 0.07 \\times 1.78333\\right)$
$L_E = 2000 \\times \\left(1 + 0.1248331\\right)$
$L_E = 2000 \\times 1.1248331$
$L_E = 2249.6662 \\text{ m}$
Approximately, the runway length corrected for elevation is $2250 \\text{ m}$.
The second sequential correction is for temperature. Higher temperatures reduce air density, which again impacts aircraft lift and engine thrust, necessitating a longer runway.
We calculate the difference between the Airport Reference Temperature (ART) and the standard temperature at the airport's elevation ($T_s$).
Temperature difference ($T_d$) is calculated as:
$T_d = \\text{Airport Reference Temperature} - \\text{Standard Temperature at Elevation}$
$T_d = T_a - T_s$
Substituting the values:
$T_d = 22.65^\circ \\text{C} - 11.5225^\circ \\text{C}$
$T_d = 11.1275^\circ \\text{C}$
ICAO specifies an increase in runway length by $1\\%$ for every $1^\circ \\text{C}$ rise of the Airport Reference Temperature above the standard atmospheric temperature at the airport elevation. This correction is applied to the length already corrected for elevation ($L_E$).
The formula for runway length corrected for temperature ($L_T$) is:
$L_T = L_E \\times \\left(1 + \\frac{1}{100} \\times T_d\\right)$
Substituting the values:
$L_T = 2249.6662 \\text{ m} \\times \\left(1 + \\frac{1}{100} \\times 11.1275\\right)$
$L_T = 2249.6662 \\times \\left(1 + 0.111275\\right)$
$L_T = 2249.6662 \\times 1.111275$
$L_T = 2500.22 \\text{ m}$
After applying sequential corrections for elevation and temperature, the length of the runway required is approximately $2500 \\text{ m}$. This value aligns with one of the provided options.
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Calculate the turning radius of the taxiway for an airport serving large subsonic jet planes. The design speed of turning is 60 kmph and assume friction coefficient between tyre and pavement surface as 0.15.
What is the airport reference temperature, if the monthly mean of average daily temperature for the hottest month of a study year = 24°C and the monthly mean of the maximum daily temperature for the same month of the same year = 30°C
Match the items in List 1 (Purpose) with those in List 2 (Designed Component used in Airport, and select the answer using codes given below.
List – I | List – II | ||
A. | Basic Runway length | 1. | Width and length of Safety area of airport |
B. | Runway Capacity | 2. | Housing, Servicing of aircrafts |
C. | Runway geometric design | 3. | Location of exit taxiways |
D. | Hangar | 4. | Engine failure class |