A rigid circular disc of radius $r$ (in m) is rolling without slipping on a flat surface as shown in the figure below. The angular velocity of the disc is $\omega$ (in rad s$^{-1}$). The velocities (in m s$^{-1}$) at points O and A, respectively, are
To solve the problem, we need to determine the velocities of points O and A on a rigid circular disc rolling without slipping on a flat surface.

Given:
Concept: For a disc rolling without slipping on a flat surface, the point of contact (point A) with the ground has zero velocity, as it momentarily comes to rest before rolling over.
Velocity at Point O:
The center of the disc (point O) moves with a velocity due to the rotation of the disc. The linear velocity v_O of point O is given by:
v_O = r\omega
The direction of this velocity is along the horizontal axis (positive \hat{i} direction), hence:
v_O = r\omega \hat{i}
Velocity at Point A:
Point A is the point of contact with the ground during rolling without slipping. At any instant, the velocity of this point is zero because it is instantaneously at rest:
v_A = 0
Therefore, the velocities at points O and A are r\omega\hat{i} and 0, respectively.
Conclusion: The correct answer is r\omega\hat{i} and 0.
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Each of four particles move along an x-axis. Their coordinates (in meters) as functions of time (in seconds) are given by
1) particle 1: x (t) = 3.5 – 2.7 t3
2) particle 2: x (t) = 3.5 + 2.7 t3
3) particle 3: x (t) = 3.5 – 2.7 t2
4) particle 4: x (t) = 3.5 – 3.4t - 2.7 t2
Which of these particles have constant acceleration?
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