A rectangle has its longer side 2 cm greater than its shorter side. Its area is 80 cm². Find the perimeter of the rectangle (in cm).
36
We are given a rectangle where the longer side is 2 cm greater than the shorter side. The area of the rectangle is 80 cm². We need to find the perimeter of this rectangle.
Let's denote the shorter side of the rectangle as \(w\) cm.
According to the problem, the longer side (\(l\)) is 2 cm greater than the shorter side. So, we can express the longer side as \(l = w + 2\) cm.
The area of a rectangle is calculated by multiplying its length and width (Area = \(l \times w\)).
We are given that the area is 80 cm². Substituting the expressions for \(l\) and \(w\), we get the equation:
\(w \times (w + 2) = 80\)
Now, let's solve this equation for \(w\):
\(w^2 + 2w = 80\)
To solve this quadratic equation, we move all terms to one side:
\(w^2 + 2w - 80 = 0\)
We can solve this quadratic equation by factoring. We need to find two numbers that multiply to -80 and add up to +2. These numbers are 10 and -8.
So, we can factor the equation as:
\((w + 10)(w - 8) = 0\)
This equation gives us two possible values for \(w\):
Since \(w\) represents the length of a side of the rectangle, it must be a positive value. Therefore, we take the positive solution:
\(w = 8\) cm
The shorter side \(w = 8\) cm.
The longer side \(l = w + 2 = 8 + 2 = 10\) cm.
So, the dimensions of the rectangle are 8 cm and 10 cm.
Let's quickly check the area: \(8 \times 10 = 80\) cm², which matches the given information.
The perimeter of a rectangle is calculated using the formula: Perimeter = \(2 \times (\text{length} + \text{width})\).
Using the side lengths we found (\(l = 10\) cm and \(w = 8\) cm):
Perimeter = \(2 \times (10 + 8)\)
Perimeter = \(2 \times (18)\)
Perimeter = \(36\) cm
The perimeter of the rectangle is 36 cm.
| Concept | Formula | Notes |
|---|---|---|
| Area of a Rectangle | \(A = l \times w\) | \(l\) = length, \(w\) = width |
| Perimeter of a Rectangle | \(P = 2 \times (l + w)\) | Sum of all four sides |
| Solving Quadratic Equations | \(ax^2 + bx + c = 0\) | Can be solved by factoring, completing the square, or quadratic formula. |
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