A rain gauge recorded hourly rainfall as 5 cm, 2 cm, 4 cm and 3 cm for a four hour storm respectively. If the φ- index was 3 cm/hour, the total direct runoff from a catchment for the storm was
3 cm
This question involves calculating the total direct runoff from a catchment during a storm, given the hourly rainfall measurements and the $\phi$-index ($\phi$-index).
The $\phi$-index represents the average rate of water loss from a storm, including factors like infiltration, depression storage, and interception. It's a common method used in hydrology to estimate direct runoff. Rainfall intensity exceeding the $\phi$-index during a storm contributes to the direct runoff.
We are given the following hourly rainfall data for a four-hour storm:
The $\phi$-index is given as 3 cm/hour.
To find the direct runoff for each hour, we compare the rainfall intensity for that hour with the $\phi$-index. Direct runoff occurs only when the rainfall intensity is greater than the $\phi$-index. The amount of direct runoff for that hour is calculated as:
Direct Runoff (per hour) = Rainfall Intensity (per hour) - $\phi$-index
If Rainfall Intensity $\leq$ $\phi$-index, then Direct Runoff = 0.
Let's apply this to the given data:
The total direct runoff is the sum of the direct runoff from each hour:
Total Direct Runoff = (Runoff Hour 1) + (Runoff Hour 2) + (Runoff Hour 3) + (Runoff Hour 4)
Total Direct Runoff = 2 cm + 0 cm + 1 cm + 0 cm
Total Direct Runoff = 3 cm
Therefore, the total direct runoff from the catchment for the storm was 3 cm.
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