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Question

A pushdown automaton behaves like a Turing machine when the number of total memory is:

The correct answer is

2 or more

Understanding Pushdown Automata and Turing Machines

The question asks about the conditions under which a Pushdown Automaton (PDA) can achieve the computational power of a Turing Machine (TM). Let's first understand what each type of automaton is and how they handle memory.

What is a Pushdown Automaton (PDA)?

A standard Pushdown Automaton is a model of computation that consists of:

  • A finite control (like a Finite Automaton).
  • An input tape (read-only).
  • One stack as auxiliary memory. The stack allows pushing and popping elements according to the Last-In, First-Out (LIFO) principle.

PDAs with a single stack are used to recognize context-free languages.

What is a Turing Machine (TM)?

A Turing Machine is a more powerful model of computation that consists of:

  • A finite control.
  • An input/work tape (read-write, potentially infinite in both directions).
  • A head that can read from and write to the tape, and move left or right.

Turing Machines are considered the most powerful computational model for algorithms and can recognize recursively enumerable languages.

Comparing Power: PDA vs. TM

Turing Machines are strictly more powerful than standard Pushdown Automata. There are languages that a TM can recognize but a standard PDA cannot (e.g., the language \(\{a^n b^n c^n \mid n \ge 0\}\)).

Increasing PDA Power with More Memory

The key difference in power lies in the memory. A standard PDA's single stack has limitations compared to a TM's tape. What happens if we give a PDA more memory?

It turns out that giving a PDA additional stacks significantly increases its computational power. Specifically:

  • A PDA with two stacks can simulate a Turing Machine. Each stack can effectively simulate one half of the Turing Machine's infinite tape.
  • Adding more stacks beyond two (e.g., three, four, or more) does not increase the computational power beyond that of a two-stack PDA. A K-stack PDA for \(K \ge 2\) is equivalent in power to a two-stack PDA, and thus equivalent to a Turing Machine.

Analyzing the Options

The question asks about the "number of total memory". In the context of comparing PDAs and TMs, this memory refers to the auxiliary storage beyond the finite control. For a PDA, this is typically measured by the number of stacks.

Let's look at the options:

Option Number of Memory (Stacks) Computational Power Behaves like a TM?
0 0 Finite Automaton (Regular Languages) No
1 1 Standard PDA (Context-Free Languages) No (less powerful than TM)
1 or more 1 or more Starts with standard PDA (power of 1 stack), can become TM with 2+ stacks. The condition for *behaving like* a TM requires reaching that power level. Only if it has 2 or more stacks. This option includes the case of only 1 stack, which is not enough.
2 or more 2 or more Equivalent to a Turing Machine (Recursively Enumerable Languages) Yes

As established, a PDA with two or more stacks has the same computational power as a Turing Machine. Therefore, when the number of total memory (interpreted as stacks in this context) is 2 or more, a Pushdown Automaton behaves like a Turing Machine.

Conclusion on PDA Memory and TM Equivalence

A standard Pushdown Automaton with one stack is less powerful than a Turing Machine. However, by adding a second stack, the PDA gains enough memory and flexibility to simulate the operations of a Turing Machine's tape. Any additional stacks beyond the second one do not increase the power further. Thus, a PDA becomes equivalent in power to a Turing Machine when it has 2 or more stacks.

Revision Table: Automata and Memory

Automaton Type Auxiliary Memory Languages Recognized Equivalent TM Power?
Finite Automaton (FA) None (0 memory) Regular Languages No
Pushdown Automaton (PDA) 1 Stack Context-Free Languages No
Pushdown Automaton (PDA) 2 or more Stacks Recursively Enumerable Languages Yes
Turing Machine (TM) Infinite Tape Recursively Enumerable Languages By definition

Additional Information: Chomsky Hierarchy

The relationship between these automata and the languages they recognize is part of the Chomsky Hierarchy, which classifies formal languages based on their complexity:

  • Type 3: Regular Languages - Recognized by Finite Automata (0 memory).
  • Type 2: Context-Free Languages - Recognized by Pushdown Automata with 1 stack (1 memory).
  • Type 1: Context-Sensitive Languages - Recognized by Linear Bounded Automata (memory proportional to input size).
  • Type 0: Recursively Enumerable Languages - Recognized by Turing Machines (infinite memory).

Adding a second stack to a PDA elevates its power from recognizing Context-Free Languages (Type 2) to recognizing Recursively Enumerable Languages (Type 0), making it equivalent to a Turing Machine.

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Important Questions from Pushdown Automata - Teaching

  1. Consider the grammer S → SbS | a.

    Consider the following statements:

    The string abababa has

    (A) two parse trees

    (B) two left most derivations

    (C) two right most derivations

    Which of the following is correct?

  2. Consider the following NPDA = ({q 0, q 1, q f}, {a, b}, {1, z}, δ, q 0, z, {q f})

    δ(q 0, λ, z) = {(q f, z)}

    δ(q 0, a, z) = {(q 1, 11z)}

    δ(q 1, a, 1) = {(q 1, 111)}

    δ(q 1, b, 1) = {(q 1, λ)}

    δ(q 1, λ, z) = {(q f, z}

    Which of the following Language L is accepted by NPDA?

  3. What language is accepted by the pushdown automation

    M = ({q 0, q 1, q2}, {a, b}, {a, b, z}, δ, q 0, z, {q 2})

    with δ(q 0, a, a) = {(q 0, aa)}; δ(q 0, b, a) = {(q 0, ba)}

    δ(q 0, a, b) = {(q 0, ab)}; δ(q 0, b, b) = {(q 0, bb)}

    δ(q 0, a, z) = {(q 0, az)}; δ(q 0, b, z) = {(q 0, bz)}

    δ(q 0, λ, b) = {(q 1, b)}; δ(q 0, λ, a) = {(q 1, a)}

    δ(q 1, a, a) = {(q 1, λ)}; δ(q 1, b, b) = {(q 1, λ)}

    δ(q 1, λ, z) = {(q 2, z)}?

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