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Question

A protein is to be purified using ion-exchange column chromatography. The relationship between HETP (Height Equivalent to Theoretical Plate) and the linear liquid velocity of mobile phase is given by: 

$H = \frac{A}{u} + Bu + C$ 

where H is HETP (m) and u is linear liquid velocity of mobile phase ($m.s^{-1}$). The values of A, B and C are $3\times10^{-8} \ m^2.s^{-1}$, $3 \ s$ and $6\times10^{-5} \ m$, respectively. The number of theoretical plates based on minimum HETP for a column of 66 cm length will be ____________________.

HETP Equation Analysis

The Height Equivalent to Theoretical Plate (HETP) quantifies column efficiency in chromatography. The relationship provided is derived from the Van Deemter equation:

$H = \frac{A}{u} + Bu + C$

Where:

  • $H$ = HETP (m)
  • $u$ = linear liquid velocity of mobile phase ($m.s^{-1}$)
  • $A = 3\times10^{-8} \ m^2.s^{-1}$
  • $B = 3 \ s$
  • $C = 6\times10^{-5} \ m$

The column length is given as $L = 66 \ cm = 0.66 \ m$. The objective is to find the number of theoretical plates ($N$) corresponding to the minimum HETP ($H_{min}$).

Velocity for Minimum HETP

To find the minimum HETP, we first need to determine the mobile phase velocity ($u$) at which HETP is minimal. This occurs when the derivative of the HETP equation with respect to $u$ is zero:

$\frac{dH}{du} = -\frac{A}{u^2} + B$

Setting the derivative to zero:

$-\frac{A}{u^2} + B = 0 \implies u^2 = \frac{A}{B}$

Calculating the optimal velocity:

$u = \sqrt{\frac{3\times10^{-8} \ m^2.s^{-1}}{3 \ s}} = \sqrt{1\times10^{-8} \ m^2.s^{-1}} = 1\times10^{-4} \ m.s^{-1}$

Minimum HETP Calculation

Substitute the calculated optimal velocity ($u$) back into the HETP equation to find the minimum HETP ($H_{min}$):

$H_{min} = \frac{A}{u} + Bu + C$

$H_{min} = \frac{3\times10^{-8} \ m^2.s^{-1}}{1\times10^{-4} \ m.s^{-1}} + (3 \ s)(1\times10^{-4} \ m.s^{-1}) + 6\times10^{-5} \ m$

$H_{min} = 3\times10^{-4} \ m + 3\times10^{-4} \ m + 6\times10^{-5} \ m$

Combine terms:

$H_{min} = 6\times10^{-4} \ m + 0.6\times10^{-4} \ m = 6.6\times10^{-4} \ m$

Theoretical Plates Calculation

The number of theoretical plates ($N$) is determined by dividing the column length ($L$) by the minimum HETP ($H_{min}$):

$N = \frac{L}{H_{min}}$

Substitute the values:

$N = \frac{0.66 \ m}{6.6\times10^{-4} \ m}$

$N = \frac{6.6\times10^{-1}}{6.6\times10^{-4}} = 10^{-1 - (-4)} = 10^3 = 1000$

Thus, the number of theoretical plates based on the minimum HETP is 1000.

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Important Questions from Ion Exchange Gel Filtration Hydrophobic Interaction and Affinity Chromatography

  1. Which of the following separation processes is/are based on molecular size?
  2. Match the stationary phase (Column I) with its corresponding chromatography technique (Column II).
    Column IColumn II
    P. Protein A1. Size exclusion chromatography
    Q. Sephadex2. Ion-exchange chromatography
    R. Phenylsepharose3. Affinity chromatography
    S. Diethylaminoethyl cellulose4. Hydrophobic interaction chromatography
  3. A mixture contains three similarly sized peptides P, Q and R. The peptide P is positively charged, Q is weakly negative and R is strongly negative. If this mixture is passed through an ion-exchange chromatography column containing an anionic resin, their order of elution will be
  4. Two monomeric His-tagged proteins of identical molecular weight are present in a solution. pIs of these two proteins are 5.6 and 6.8. Which one of the following techniques can be used to separate them?
  5. Match the entries in the Group I with the elution conditions in Group II.

    Group IGroup II
    P. Ion-exchange chromatography1. Isocratic solvent
    Q. Hydrophobic column chromatography2. Ampholytes
    R. Gel filtration chromatography3. Increasing gradient of salt
    S. Chromatofocusing4. Decreasing gradient of polarity
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