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Question

A population size at t=0 is 80 and has a growth rate of 0.12. If the population follows logistic growth, what is the growth rate constant if the carrying capacity is 240 ?

The correct answer is
0.18

Logistic Growth Rate Constant Calculation

This solution explains how to find the growth rate constant ($r$) for a population exhibiting logistic growth, given initial population size ($N_0$), carrying capacity ($K$), and the initial per capita growth rate.

Given Parameters

  • Initial population size, $N_0 = 80$
  • Carrying capacity, $K = 240$
  • Initial per capita growth rate = $0.12$

Logistic Growth Model

The logistic growth model describes population growth that slows down as it approaches the carrying capacity ($K$). The rate of population change is given by:

$ \frac{dN}{dt} = rN \left( 1 - \frac{N}{K} \right) $

Where:

  • $\frac{dN}{dt}$ is the rate of population change
  • $r$ is the intrinsic rate of increase (the growth rate constant)
  • $N$ is the population size
  • $K$ is the carrying capacity

The per capita growth rate is represented by $\frac{1}{N} \frac{dN}{dt}$. From the logistic equation, this is:

$ \frac{1}{N} \frac{dN}{dt} = r \left( 1 - \frac{N}{K} \right) $

Calculating the Growth Rate Constant ($r$)

We are given that the initial growth rate (per capita) is $0.12$ when $N = N_0 = 80$. We can substitute the known values into the per capita growth rate equation:

  1. Set up the equation: Use the initial values in the per capita growth rate formula. $ 0.12 = r \left( 1 - \frac{N_0}{K} \right) $
  2. Substitute values: Plug in $N_0 = 80$ and $K = 240$. $ 0.12 = r \left( 1 - \frac{80}{240} \right) $
  3. Simplify the fraction: $ 0.12 = r \left( 1 - \frac{1}{3} \right) $
  4. Simplify the term in parentheses: $ 0.12 = r \left( \frac{2}{3} \right) $
  5. Solve for $r$: Rearrange the equation to isolate $r$. $ r = 0.12 \times \frac{3}{2} $ $ r = 0.12 \times 1.5 $ $ r = 0.18 $

Conclusion

The growth rate constant ($r$) for the population is $0.18$. This corresponds to Option C.

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Important Questions from Population Ecology - Teaching

  1. Assume that the population (N) of a species follows the logistic growth represented by following equation -
    $$\frac{dN}{dt} = 0.8N - 0.01N^{2}$$
    At what value of N, the population exhibits maximum growth ?
  2. Assertion (A) : The hypothesis testing can proceed on the basis of null hypothesis.
    Reason (R) : If null hypothesis is true probabilities to different possible sample result can be assigned to it.
    In the context of the two statements, which one of the following is correct ?
  3. Which of the following index is used for estimating population density?
  4. If $\Delta N_n$ is equal to production of new individual in the population, $\Delta t$ and $N$ represent time and initial number of individuals of a population, then natality rate per unit of population is
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