Logistic Growth Rate Constant Calculation
This solution explains how to find the growth rate constant ($r$) for a population exhibiting logistic growth, given initial population size ($N_0$), carrying capacity ($K$), and the initial per capita growth rate.
Given Parameters
- Initial population size, $N_0 = 80$
- Carrying capacity, $K = 240$
- Initial per capita growth rate = $0.12$
Logistic Growth Model
The logistic growth model describes population growth that slows down as it approaches the carrying capacity ($K$). The rate of population change is given by:
$ \frac{dN}{dt} = rN \left( 1 - \frac{N}{K} \right) $
Where:
- $\frac{dN}{dt}$ is the rate of population change
- $r$ is the intrinsic rate of increase (the growth rate constant)
- $N$ is the population size
- $K$ is the carrying capacity
The per capita growth rate is represented by $\frac{1}{N} \frac{dN}{dt}$. From the logistic equation, this is:
$ \frac{1}{N} \frac{dN}{dt} = r \left( 1 - \frac{N}{K} \right) $
Calculating the Growth Rate Constant ($r$)
We are given that the initial growth rate (per capita) is $0.12$ when $N = N_0 = 80$. We can substitute the known values into the per capita growth rate equation:
- Set up the equation: Use the initial values in the per capita growth rate formula.
$ 0.12 = r \left( 1 - \frac{N_0}{K} \right) $
- Substitute values: Plug in $N_0 = 80$ and $K = 240$.
$ 0.12 = r \left( 1 - \frac{80}{240} \right) $
- Simplify the fraction:
$ 0.12 = r \left( 1 - \frac{1}{3} \right) $
- Simplify the term in parentheses:
$ 0.12 = r \left( \frac{2}{3} \right) $
- Solve for $r$: Rearrange the equation to isolate $r$.
$ r = 0.12 \times \frac{3}{2} $
$ r = 0.12 \times 1.5 $
$ r = 0.18 $
Conclusion
The growth rate constant ($r$) for the population is $0.18$. This corresponds to Option C.