A point source in the air is placed at a distance of 40 cm in front of a spherical convex glass surface (μ 2 = 1.5) of radius of curvature 10 cm. The image of the source is formed at a distance of _______ from the surface in the direction of incident light.
60 cm
Understanding how light behaves when it passes through different media is fundamental in optics. This problem involves a point source and a spherical convex glass surface, requiring the application of the spherical refraction formula to determine the image location.
When light travels from one medium to another through a spherical surface, its path changes. This phenomenon is known as refraction. The relationship between object distance, image distance, radii of curvature, and refractive indices is described by the spherical refraction formula. This formula is crucial for solving problems involving image formation by spherical surfaces, whether convex or concave.
Let's identify the given values from the question for accurate calculation of the image position formed by the spherical convex glass surface:
To find the image distance (\(v\)), we use the formula for refraction at a single spherical surface:
\[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \]
Now, substitute the known values into the formula:
\[ \frac{1.5}{v} - \frac{1}{-40} = \frac{1.5 - 1}{10} \]
Simplify the equation:
\[ \frac{1.5}{v} + \frac{1}{40} = \frac{0.5}{10} \]
\[ \frac{1.5}{v} + \frac{1}{40} = \frac{1}{20} \]
Isolate the term with \(v\):
\[ \frac{1.5}{v} = \frac{1}{20} - \frac{1}{40} \]
Find a common denominator for the right side:
\[ \frac{1.5}{v} = \frac{2}{40} - \frac{1}{40} \]
\[ \frac{1.5}{v} = \frac{1}{40} \]
Solve for \(v\):
\[ v = 1.5 \times 40 \]
\[ v = 60 \text{ cm} \]
The calculated image distance \(v = +60\) cm is positive. In the Cartesian sign convention, a positive image distance means that the image is formed on the side where the refracted light exits the surface. For a spherical convex glass surface, if the object is in air and light passes into glass, a positive image distance implies the image is formed inside the glass, on the side of the incident light's propagation direction. This indicates that the image formed is a real image.
The image of the point source placed in front of the spherical convex glass surface is formed at a distance of 60 cm from the surface in the direction of the incident light. This result aligns with the principles of refraction at spherical surfaces and typical image formation scenarios for convex refracting surfaces.
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