A plate of size 100 mm x 10 mm having yield strength of 250 MPa, the design strength of plate in yielding of the cross-section is
227 kN
This solution explains how to calculate the design strength of a steel plate based on its cross-section yielding, a critical concept in structural engineering.
The design strength of a steel member against yielding is determined by its gross cross-sectional area and the material's yield strength. It represents the maximum stress the plate can withstand before permanent deformation occurs, considering safety factors.
The design strength of a plate in yielding of the gross section ($T_{dg}$) is calculated using the following formula, typically based on structural design codes like IS 800:
$$ T_{dg} = \frac{A_g f_y}{\gamma_{m0}} $$
Where:
The plate dimensions are given as 100 mm x 10 mm.
$$ A_g = \text{Width} \times \text{Thickness} $$
$$ A_g = 100 \text{ mm} \times 10 \text{ mm} = 1000 \text{ mm}^2 $$
The yield strength is provided as 250 MPa.
$$ f_y = 250 \text{ MPa} = 250 \text{ N/mm}^2 $$
For yielding in the gross section, the partial safety factor commonly used in structural steel design is $\gamma_{m0} = 1.10$.
Substitute the values into the formula:
$$ T_{dg} = \frac{A_g f_y}{\gamma_{m0}} $$
$$ T_{dg} = \frac{1000 \text{ mm}^2 \times 250 \text{ N/mm}^2}{1.10} $$
$$ T_{dg} = \frac{250000 \text{ N}}{1.10} $$
$$ T_{dg} \approx 227272.72 \text{ N} $$
To convert Newtons (N) to Kilonewtons (kN), divide by 1000.
$$ T_{dg} \approx \frac{227272.72}{1000} \text{ kN} $$
$$ T_{dg} \approx 227.27 \text{ kN} $$
The calculated design strength of the steel plate in yielding of the cross-section is approximately 227.27 kN. This value closely matches one of the provided options.
A single angle in tension is connected by one leg only. If the areas of connecting and outstanding legs are respectively a and b, then what is the net effective area of the angle?
A) \(a-\frac{b}{1+0.35\times\frac{b}{a}}\)
B) \(a+\frac{b}{1+0.35\times\frac{b}{a}}\)
C) \(a-\frac{b}{1+0.20\times\frac{b}{a}}\)
D) \(a+\frac{b}{1+0.20\times\frac{b}{a}}\)
The net area of round bars to resist the tension, is the area of the cross-section at
A steel plate is 300 mm wide and 10 mm thick. It has one rivet of nominal diameter 18 mm. The net sectional area of the plate is
The best tension member section will be as:
For preliminary sizing, the rupture strength of net section may be approximately taken by using the below equation as per IS ∶ 800-2007,
Tdn = αAnfu/γml
What is the "α" value for one or two bolts along the length in the end connection or equivalent weld length.