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Question

A plastically deformed metal crystal at low temperature exhibits wavy slip line pattern due to

The correct answer is
Large number of slip systems

Metal Crystal Deformation: Wavy Slip Lines Explained

Plastic deformation in metals occurs through the movement of dislocations. Dislocations travel along specific crystallographic planes and directions, collectively termed a slip system.

At low temperatures, the primary mechanism for plastic deformation is slip. The resulting pattern of slip lines observed on a metal's surface is strongly dependent on the number of available slip systems.

When a metal crystal possesses a large number of slip systems, dislocations find it easier to switch between different planes during their movement. This tendency to change slip planes, known as cross-slip, results in the formation of irregular and wavy slip line patterns.

Analysis of Potential Causes

  • Dislocation pile-up: This occurs when dislocations are blocked, leading to stress concentration. It is a consequence of deformation, not the primary reason for the wavy pattern itself.
  • Large number of slip systems: This factor directly explains the wavy pattern, as it allows for extensive cross-slip, making dislocation paths non-linear.
  • Low stacking fault energy: While it influences dislocation behavior (e.g., dissociation), it is not the direct cause of wavy slip lines compared to the availability of multiple slip planes.
  • Dislocation climb: This mechanism involves atomic diffusion and is characteristic of high-temperature deformation. It is not significant at low temperatures where slip is dominant.
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Important Questions from Defects Dislocation Stress Field Burgers Vector

  1. Which one of the following dislocation dissociation reactions is feasible in face-centered cubic metals?
  2. With reference to edge and screw dislocations, which of the following statements is/are CORRECT?
  3. The Burger's vector of a dislocation in a cubic crystal (with lattice parameter a) is $\frac{a}{2}[110]$ and dislocation line is along $[112]$ direction. The angle (in degrees) between the dislocation line and its Burger's vector is _________

  4. The c/a ratio of Zn (hcp) is 1.856. Slip at room temperature occurs most easily on which of the following slip systems in Zn:
    Note: In hcp metals, the ideal c/a ratio is 1.633.
  5. Determine the correctness (or otherwise) of the following Assertion [A] and the Reason [R]
    Assertion [A]: Refractory BCC metals like W and Mo are less ductile than FCC metals like Ni and Pt at room temperature
    Reason [R]: BCC metals have fewer independent slip systems than FCC metals
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