All Exams Test series for 1 year @ ₹349 only
Question

A person sold an article at a loss of 15%. Had he sold it for Rs. 30.60 more, he would have gained 9%. To gain 10%, he should have sold it for:

The correct answer is

Rs. 140.25

Let's break down this profit and loss problem step by step to find the selling price needed to achieve a 10% gain.

The problem states that an article was initially sold at a loss of 15%. If the selling price were Rs. 30.60 more, it would have resulted in a gain of 9%. We need to find the selling price required to make a gain of 10%.

Understanding Profit and Loss Concepts

In profit and loss calculations, we usually work with the Cost Price (CP) and the Selling Price (SP). Percentage gain or loss is always calculated on the Cost Price unless stated otherwise.

  • Loss % = $\frac{\text{Loss}}{\text{CP}} \times 100$
  • Gain % = $\frac{\text{Gain}}{\text{CP}} \times 100$
  • If there is a loss of $L\%$, then $SP = CP \times (100-L)/100$.
  • If there is a gain of $G\%$, then $SP = CP \times (100+G)/100$.

Step-by-Step Solution for Finding the Cost Price

Let the Cost Price of the article be $CP$.

Scenario 1: Sold at a loss of 15%

The selling price (SP1) in this case is:

$SP1 = CP \times \frac{(100 - 15)}{100} = CP \times \frac{85}{100} = 0.85 \times CP$

Scenario 2: Sold with a gain of 9%

The selling price (SP2) in this case is:

$SP2 = CP \times \frac{(100 + 9)}{100} = CP \times \frac{109}{100} = 1.09 \times CP$

According to the problem, if the article was sold for Rs. 30.60 more than the first selling price (SP1), it would be equal to the second selling price (SP2). So, we can write the equation:

$SP2 = SP1 + 30.60$

Substitute the expressions for SP1 and SP2 in terms of CP:

$1.09 \times CP = 0.85 \times CP + 30.60$

Now, let's solve for CP:

$1.09 \times CP - 0.85 \times CP = 30.60$

$(1.09 - 0.85) \times CP = 30.60$

$0.24 \times CP = 30.60$

$CP = \frac{30.60}{0.24}$

$CP = \frac{3060}{240}$ (Multiplying numerator and denominator by 100)

$CP = \frac{306}{24}$ (Dividing numerator and denominator by 10)

$CP = \frac{102}{8}$ (Dividing numerator and denominator by 3)

$CP = \frac{51}{4}$ (Dividing numerator and denominator by 2)

$CP = 12.75 \times 10$ (Since 51/4 = 12.75 and we had 306/24 = 102/8. Let's recheck: 30.60/0.24 = 3060/24 = 127.5)

Let's calculate $3060 \div 240$: $3060/240 = 306/24$. $306 \div 24 = 12.75$. So $CP = 127.50$.

The Cost Price (CP) of the article is Rs. 127.50.

Calculating Selling Price for 10% Gain

Now we need to find the selling price (SP3) at which the person would gain 10%. The gain is calculated on the Cost Price (CP).

Gain required = 10% of CP

Selling Price (SP3) = $CP + (10\% \text{ of } CP)$

$SP3 = CP \times \frac{(100 + 10)}{100} = CP \times \frac{110}{100} = 1.10 \times CP$

Substitute the value of CP we found:

$SP3 = 1.10 \times 127.50$

$SP3 = 1.1 \times 127.5 = 140.25$

So, to gain 10%, the person should have sold the article for Rs. 140.25.

Let's verify the steps:

  • CP = 127.50
  • 15% Loss: $127.50 \times 0.85 = 108.375$ (approx Rs. 108.38)
  • 9% Gain: $127.50 \times 1.09 = 139.975$ (approx Rs. 139.98)
  • Difference: $139.975 - 108.375 = 31.6$ (The difference in the problem is 30.60. Let's recheck calculation $30.60 / 0.24$). $30.60 / 0.24 = (3060/100) / (24/100) = 3060/24$. $3060 \div 24$. $3060/24 = 127.5$. Okay, CP is indeed 127.50. SP1 = $127.50 \times 0.85 = 108.375$. SP2 = $127.50 \times 1.09 = 138.975$. Difference = $138.975 - 108.375 = 30.60$. This matches the problem statement exactly.
  • 10% Gain SP: $127.50 \times 1.10 = 140.25$.

The calculation is correct.

The selling price required to gain 10% is Rs. 140.25.

Concept Formula / Value
Let Cost Price (CP) $CP$
Selling Price at 15% Loss (SP1) $0.85 \times CP$
Selling Price at 9% Gain (SP2) $1.09 \times CP$
Given Difference (SP2 - SP1) Rs. 30.60
Equation to find CP $1.09 \times CP - 0.85 \times CP = 30.60$
Calculated CP Rs. 127.50
Target Gain 10%
Target Selling Price (SP3) $1.10 \times CP$
Calculated SP3 Rs. 140.25

Revision Table: Profit and Loss Basics

Term Definition Calculation
Cost Price (CP) The price at which an article is bought. Base value for profit/loss percentage.
Selling Price (SP) The price at which an article is sold. Result of transaction.
Profit When SP > CP. Profit = SP - CP
Loss When SP < CP. Loss = CP - SP
Profit % Profit as a percentage of CP. $\frac{\text{Profit}}{\text{CP}} \times 100$
Loss % Loss as a percentage of CP. $\frac{\text{Loss}}{\text{CP}} \times 100$

Additional Information on Profit and Loss Calculations

Profit and loss problems often involve converting between cost price, selling price, profit percentage, and loss percentage. A key point is always identifying the base for the percentage calculation, which is usually the cost price.

In this problem, the difference in selling prices corresponds to the combined percentage change from 15% loss to 9% gain. The total percentage change is $15\% (\text{loss}) + 9\% (\text{gain}) = 24\%$. This 24% corresponds to the difference of Rs. 30.60. So, $24\%$ of $CP = 30.60$. This confirms our equation $0.24 \times CP = 30.60$. Understanding this relationship can sometimes provide a quicker way to set up the problem.

Once the Cost Price is known, calculating the selling price for any desired profit or loss percentage is straightforward using the formulas $SP = CP \times (1 + \text{gain %}/100)$ or $SP = CP \times (1 - \text{loss %}/100)$.

Was this answer helpful?

Important Questions from Mixture Problems

  1. A mixture of acid and water contains 20 percent acid. When 10 litres of water is added to the mixture, then the percentage of acid becomes 15 percent. What is the original quantity of mixture ?

  2. A container contains 20 L mixture in which there is 10% sulphuric acid. Find the quantity of sulphuric acid to be added in it to make the solution to contain 25% sulphuric acid.

  3. The ratio of milk to water in a 100 litres mixture is 2 ∶ 3. 10 litres of this mixture is withdrawn and replaced with milk. This process is repeated 2 more times, What is the percentage of milk in final mixture ?

  4. 80% and 90% pure acid solutions are mixed to obtain 20 litres of 87% pure acid solution. Find the quantity (in litres) of 80% pure acid solution taken to form the mixture.
  5. Some fruits are bought at a rate of 11 for Rs. 100 and an equal number at a rate of 9 for Rs. 100. If all the fruits are sold at a rate of 10 for Rs. 100, then what is the gain or loss percent in the entire transaction?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App