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Question

A number was divided by 9, instead of being multiplied by 9. As a result of this, there was an error in the answer. What is the percentage difference (correct to two decimal places) in the answer due to this miscalculation?

The correct answer is 98.77%

In this problem, we need to find the percentage difference in an answer when a number was mistakenly divided by 9 instead of being multiplied by 9. This kind of miscalculation can lead to a significant error, and understanding how to quantify it is important.

Percentage Difference Miscalculation Explained

Let's assume the original number is represented by the variable x. We will first determine the correct result and then the incorrect result due to the miscalculation.

Correct Answer Calculation

The problem states that the number was supposed to be multiplied by 9. Therefore, the correct answer, let's call it Correct Value, would be:

Correct Value $$ = \text{Number} \times 9 $$

Correct Value $$ = x \times 9 = 9x $$

Incorrect Answer due to Division

Instead of multiplication, the number was divided by 9. So, the incorrect answer, let's call it Incorrect Value, would be:

Incorrect Value $$ = \text{Number} \div 9 $$

Incorrect Value $$ = x \div 9 = \frac{x}{9} $$

Calculating the Difference in Answers

To find the error, we need to calculate the difference between the Correct Value and the Incorrect Value. This difference tells us how much the miscalculation affected the result.

Difference $$ = \text{Correct Value} - \text{Incorrect Value} $$

Difference $$ = 9x - \frac{x}{9} $$

To subtract these, we find a common denominator, which is 9:

Difference $$ = \frac{9x \times 9}{9} - \frac{x}{9} $$

Difference $$ = \frac{81x - x}{9} $$

Difference $$ = \frac{80x}{9} $$

Determining Percentage Difference

The percentage difference is calculated by dividing the Difference by the Correct Value and then multiplying by 100%. This shows the error as a proportion of what the answer should have been.

Percentage Difference $$ = \frac{\text{Difference}}{\text{Correct Value}} \times 100\% $$

Substitute the values we found:

Percentage Difference $$ = \frac{\frac{80x}{9}}{9x} \times 100\% $$

To simplify the fraction, remember that dividing by $9x$ is the same as multiplying by $\frac{1}{9x}$:

Percentage Difference $$ = \frac{80x}{9 \times 9x} \times 100\% $$

Percentage Difference $$ = \frac{80x}{81x} \times 100\% $$

The x terms cancel out:

Percentage Difference $$ = \frac{80}{81} \times 100\% $$

Now, perform the division and multiplication:

Percentage Difference $$ \approx 0.98765432 \times 100\% $$

Percentage Difference $$ \approx 98.765432\% $$

Rounding to Two Decimal Places

The question asks for the percentage difference corrected to two decimal places. We look at the third decimal place. If it is 5 or greater, we round up the second decimal place.

The third decimal place is 5. So, we round up 76 to 77.

Percentage Difference $$ \approx 98.77\% $$

Therefore, the percentage difference in the answer due to this miscalculation is approximately 98.77%.

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Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

  2. A sphere of volume V is made of a material with lower density than water. While on Earth, it floats on water with its volume f1V (f1 < 1) submerged. On the other hand, on a spaceship accelerating with acceleration a < g (g is the acceleration due to gravity on Earth) in outer space, its submerged volume in water is f2V. Then:

  3. A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :

  4. Consider the following statements:

    1. Distance between the longitudes becomes zero on North Pole and South Pole.

    2. Distance between the longitudes is maximum on the Equator.

    3. Number of longitudes is more than number of latitudes.

    Which of the statements given above is/are correct?

  5. One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :

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