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Question

A multiple choice exam has 4 questions, each with 4 answer choices. Every question has only one correct answer. The probability of getting all answers correct by independent random guesses for each one is

The correct answer is

(1/4)4

Probability of Getting All Answers Correct

This question asks for the probability of getting all answers correct on a multiple choice exam by random guessing. The exam has 4 questions, and each question has 4 answer choices, with only one correct answer per question.

Understanding Probability for One Question

For any single question, there are 4 possible answer choices. Since we are guessing randomly and only one choice is correct, the probability of selecting the correct answer for that single question is the number of correct choices divided by the total number of choices.

  • Number of correct choices = 1
  • Total number of choices = 4
  • Probability of getting one question correct = $\frac{1}{4}$

Calculating Probability for Multiple Independent Questions

The problem states that the guesses for each question are independent. This means that the outcome of guessing one question's answer does not affect the outcome of guessing any other question's answer.

To find the probability of multiple independent events all occurring, we multiply the probabilities of each individual event.

In this case, we want to find the probability of getting the first question correct AND the second question correct AND the third question correct AND the fourth question correct.

  • Probability of getting Question 1 correct = $\frac{1}{4}$
  • Probability of getting Question 2 correct = $\frac{1}{4}$
  • Probability of getting Question 3 correct = $\frac{1}{4}$
  • Probability of getting Question 4 correct = $\frac{1}{4}$

The probability of getting all 4 questions correct is the product of these individual probabilities:

$$ \text{Probability (all correct)} = \text{P(Q1 correct)} \times \text{P(Q2 correct)} \times \text{P(Q3 correct)} \times \text{P(Q4 correct)} $$

$$ \text{Probability (all correct)} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} $$

$$ \text{Probability (all correct)} = \left(\frac{1}{4}\right)^4 $$

Final Probability Value

Calculating the value:

$$ \left(\frac{1}{4}\right)^4 = \frac{1^4}{4^4} = \frac{1}{256} $$

So, the probability of getting all 4 questions correct by independent random guesses is $\left(\frac{1}{4}\right)^4$ or $\frac{1}{256}$.

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Important Questions from Probability

  1. Three dice are thrown. What is the probability of getting a sum which is a perfect square?

  2. Two distinct natural numbers from 1 to 9 are picked at random. What is the probability that their product has 1 in its unit place?

  3. Two dice are thrown. What is the probability that difference of numbers on them is 2 or 3 ?

  4. Suppose that there is a chance for a newly constructed building to collapse, whether the design is faulty or not. The chance that the design is faulty is 10%. The chance that the building collapses is 95% if the design is faulty, otherwise it is 45%. If it is seen that the building has collapsed, then what is the probability that it is due to faulty design?

  5. What is the probability that all three boys sit together?

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