A multiple choice exam has 4 questions, each with 4 answer choices. Every question has only one correct answer. The probability of getting all answers correct by independent random guesses for each one is
(1/4)4
This question asks for the probability of getting all answers correct on a multiple choice exam by random guessing. The exam has 4 questions, and each question has 4 answer choices, with only one correct answer per question.
For any single question, there are 4 possible answer choices. Since we are guessing randomly and only one choice is correct, the probability of selecting the correct answer for that single question is the number of correct choices divided by the total number of choices.
The problem states that the guesses for each question are independent. This means that the outcome of guessing one question's answer does not affect the outcome of guessing any other question's answer.
To find the probability of multiple independent events all occurring, we multiply the probabilities of each individual event.
In this case, we want to find the probability of getting the first question correct AND the second question correct AND the third question correct AND the fourth question correct.
The probability of getting all 4 questions correct is the product of these individual probabilities:
$$ \text{Probability (all correct)} = \text{P(Q1 correct)} \times \text{P(Q2 correct)} \times \text{P(Q3 correct)} \times \text{P(Q4 correct)} $$
$$ \text{Probability (all correct)} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} $$
$$ \text{Probability (all correct)} = \left(\frac{1}{4}\right)^4 $$
Calculating the value:
$$ \left(\frac{1}{4}\right)^4 = \frac{1^4}{4^4} = \frac{1}{256} $$
So, the probability of getting all 4 questions correct by independent random guesses is $\left(\frac{1}{4}\right)^4$ or $\frac{1}{256}$.
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