A metal wire is subjected to a constant potential difference. When the temperature of the metal wire increases, the drift velocity of the electrons in it:
Decreases, thermal velocity of the electrons increases
When a metal wire is connected to a constant potential difference, an electric field is established within the wire. This electric field exerts a force on the free electrons, causing them to drift in a direction opposite to the field. This average velocity with which the electrons drift is called the drift velocity.
Simultaneously, the electrons in a metal are constantly in random motion due to their thermal energy. This random motion velocity is called the thermal velocity. The thermal velocity of electrons is generally much higher than the drift velocity under normal conditions.
Let's analyse how increasing the temperature of the metal wire affects both the drift velocity and the thermal velocity of the electrons.
Temperature is a measure of the average kinetic energy of the particles in a substance. In the case of a metal, increasing the temperature means increasing the average kinetic energy of the free electrons and the vibrating lattice atoms (ions).
The drift velocity of electrons in a metal wire is related to the electric field, the charge of the electron, its mass, and the average time between collisions ($\tau$) with the lattice ions or other imperfections. The relationship is often expressed as:
\(\vec{v}_d = - \frac{e\vec{E}}{m} \tau\)
where \(e\) is the electron charge, \(\vec{E}\) is the electric field, \(m\) is the electron mass, and \(\tau\) is the average relaxation time (time between collisions).
When the temperature of the metal wire increases:
Alternatively, we can consider the effect on resistance. For most metals, resistance increases with temperature. Since the potential difference \(V\) is constant, by Ohm's Law (\(V = IR\)), if resistance \(R\) increases, the current \(I\) must decrease (\(I = V/R\)). The current \(I\) is also related to the drift velocity \(v_d\) by the equation \(I = nAe v_d\), where \(n\) is the number density of free electrons, \(A\) is the cross-sectional area of the wire, and \(e\) is the electron charge. Since \(n\), \(A\), and \(e\) are relatively constant with temperature, a decrease in current \(I\) implies a decrease in the drift velocity \(v_d\).
Based on the analysis:
Comparing this with the given options, the statement "Decreases, thermal velocity of the electrons increases" correctly describes what happens to the drift velocity and the thermal velocity, respectively, when the temperature of the metal wire increases.
| Property | Effect of Increasing Temperature | Explanation |
|---|---|---|
| Thermal Velocity | Increases | Higher thermal energy leads to faster random electron motion. |
| Collision Frequency | Increases | More vigorous lattice vibrations cause more frequent collisions. |
| Relaxation Time (\(\tau\)) | Decreases | Average time between collisions becomes shorter. |
| Resistance (\(R\)) | Increases | Increased collision frequency hinders electron flow. |
| Current (\(I\), for constant \(V\)) | Decreases | According to Ohm's Law (\(I=V/R\)). |
| Drift Velocity (\(v_d\)) | Decreases | Reduced relaxation time or decreased current density (\(v_d = I / (nAe)\)). |
It is important to understand the vast difference in magnitude between thermal velocity and drift velocity.
Even though the drift velocity is small, the sheer number density (\(n\)) of free electrons in a metal is extremely high (about \(10^{28}\) electrons per cubic meter), which results in a significant electric current (\(I = nAe v_d\)).
Increasing temperature dramatically increases the thermal velocity but significantly impedes the directed drift motion, thus decreasing the drift velocity and increasing resistance.
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