A man weighing 150 lbs has a 30% body fat. How much this man shall weigh, if he reduces his fat% to 25?
140 lbs
This problem involves understanding how changes in body composition, specifically body fat percentage, affect total body weight while assuming lean body mass remains constant. We need to calculate the initial lean body mass and then use the new fat percentage to find the new total weight.
Body weight is generally composed of two main components:
In scenarios like this, where a person loses weight by reducing body fat, it is typically assumed that the lean body mass remains constant unless stated otherwise. The reduction in total weight comes from the loss of fat.
The man initially weighs 150 lbs and has 30% body fat.
Initial Fat Weight = Initial Total Weight $\times$ Initial Fat Percentage
Initial Fat Weight = $150 \text{ lbs} \times 30\%$
Initial Fat Weight = $150 \text{ lbs} \times \frac{30}{100}$
Initial Fat Weight = $150 \text{ lbs} \times 0.30$
Initial Fat Weight = $45 \text{ lbs}$
The lean body mass is the total weight minus the fat weight.
Initial Lean Body Mass = Initial Total Weight - Initial Fat Weight
Initial Lean Body Mass = $150 \text{ lbs} - 45 \text{ lbs}$
Initial Lean Body Mass = $105 \text{ lbs}$
The man reduces his body fat to 25%. This means that in the new state, the lean body mass will constitute the remaining percentage of the total weight.
New Lean Body Mass Percentage = $100\%$ - New Fat Percentage
New Lean Body Mass Percentage = $100\%$ - $25\%$
New Lean Body Mass Percentage = $75\%$
We know the Lean Body Mass remains constant at 105 lbs, and this LBM now represents 75% of the New Total Weight.
New Lean Body Mass = New Total Weight $\times$ New Lean Body Mass Percentage
$105 \text{ lbs} = \text{New Total Weight} \times 75\%$
$105 \text{ lbs} = \text{New Total Weight} \times \frac{75}{100}$
$105 \text{ lbs} = \text{New Total Weight} \times 0.75$
To find the New Total Weight, we rearrange the equation:
New Total Weight = $\frac{105 \text{ lbs}}{0.75}$
New Total Weight = $140 \text{ lbs}$
So, if the man reduces his body fat percentage to 25% while maintaining his lean body mass, his new weight will be 140 lbs.
| Metric | Initial State | New State |
|---|---|---|
| Total Weight | 150 lbs | ? (Let's call it Wnew) |
| Body Fat % | 30% | 25% |
| Body Fat (lbs) | $150 \times 0.30 = 45$ lbs | $W_{new} \times 0.25$ |
| Lean Body Mass (lbs) | $150 - 45 = 105$ lbs | 105 lbs (Assumed Constant) |
Using the New State values:
Lean Body Mass + Body Fat = Total Weight
$105 \text{ lbs} + W_{new} \times 0.25 = W_{new}$
$105 \text{ lbs} = W_{new} - 0.25 W_{new}$
$105 \text{ lbs} = W_{new} (1 - 0.25)$
$105 \text{ lbs} = W_{new} \times 0.75$
$W_{new} = \frac{105 \text{ lbs}}{0.75}$
$W_{new} = 140 \text{ lbs}$
Both methods yield the same result.
Based on the calculations, if a man weighing 150 lbs with 30% body fat reduces his fat percentage to 25% while keeping his lean body mass constant, his new weight will be 140 lbs.
The final answer is $\boxed{140 lbs}$.
| Concept | Description | Formula |
|---|---|---|
| Total Body Weight | Sum of all tissues, organs, and substances in the body. | Total Weight = Fat Mass + Lean Body Mass |
| Body Fat Percentage | The proportion of total body weight that is fat. | Body Fat % = (Fat Mass / Total Weight) $\times$ 100% |
| Lean Body Mass (LBM) | Body weight minus body fat; includes muscle, bone, water, organs. | Lean Body Mass = Total Weight - Fat Mass |
| Calculating New Weight (Constant LBM) | If LBM is constant, new weight can be found if the new fat % is known. | New Total Weight = Lean Body Mass / (1 - New Fat %) |
Body composition is an important health indicator, often considered more relevant than just total body weight. It provides insight into the proportion of fat mass versus lean body mass.
This problem highlights a common scenario where fat loss leads to a change in total weight and body composition percentage, assuming the non-fat component remains stable.
The prorogation of nerve impulse from one node of Ranvier to other is called
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