A magnetic tape drive writes 600000 bytes of data while the tape moves continuously at 200 inches per second. The data recording density is 1600 bytes per inch. Each record contains 100 one-byte characters, and the blocking factor is 10 records per block. Assume an interblock gap of exactly 0.6 inch between consecutive blocks. Ignore all other recording overhead, including preambles and postambles, and exclude acceleration, stopping, and any gap before the first or after the last block. What is the elapsed time from the start of writing the first data block to the completion of the last?
3.672 sec
Step 1 — Count blocks and gaps:
Each block contains 100 × 10 = 1000 bytes. Thus there are 600000/1000 = 600 blocks and 599 gaps between them.
Step 2 — Calculate tape length:
\(L=\dfrac{600000}{1600}+599(0.6)=375+359.4=734.4\text{ inches}.\)
Step 3 — Divide by transport speed:
\(t=\dfrac{734.4}{200}=3.672\text{ s}.\)
Important Questions from File Allocation - Teaching
_______ stores entries about files and their attributes.
What is called Journaling in Linux operating system?
In a file allocation system, the following allocation schemes are used :
A. Contiguous
B. Indexed
C. Linked allocation
Which of the allocation scheme(s) given above will not suffer from external fragmentation? Choose the correct answer from the options given below :
