This problem requires calculating the concentration of Strontium (Sr) in a residual magma after fractional crystallization, using the Rayleigh equation.
Determine the fraction of residual liquid ($F$). If 60% has crystallized, the remaining liquid fraction is:
$ F = 1 - 0.60 = 0.40 $
Apply the Rayleigh equation for fractional crystallization to find the Sr concentration in the residual liquid ($C_L$). The formula is:
$ C_L = C_0 \times F^{(D-1)} $
Substitute the known values into the equation:
$ C_L = 400 \, \text{ppm} \times (0.40)^{(0.2 - 1)} $
$ C_L = 400 \, \text{ppm} \times (0.40)^{-0.8} $
Calculate the value:
$ (0.40)^{-0.8} \approx 2.09034 $
$ C_L \approx 400 \times 2.09034 \, \text{ppm} $
$ C_L \approx 836.14 \, \text{ppm} $
Round the result to the nearest integer:
$ C_L \approx 836 \, \text{ppm} $
The calculated concentration of Sr in the residual liquid is approximately 836 ppm. This value is consistent with the provided answer range.