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Question

A loan is to be returned in two equal yearly installments. If the rate of interest is 15% per annum, compounded annually and each installment is Rs. 5,819, then the total interest charged (in Rs.) is: 

The correct answer is 2,178

Loan Repayment Analysis

This problem asks us to determine the total interest charged on a loan that is repaid in two equal yearly installments. We are given the installment amount, the interest rate, and that the interest is compounded annually. To find the total interest, we first need to calculate the original principal loan amount.

Understanding Loan Installments

When a loan is repaid through equal installments, each payment consists of a part of the principal loan amount and the interest accumulated over time. To find the initial principal, we calculate the present value of each future installment. The present value is simply what a future sum of money is worth today, considering a specific interest rate.

  • Installment Amount: Each installment paid is Rs. 5,819.
  • Number of Installments: The loan is to be returned in two equal yearly installments.
  • Interest Rate: The annual interest rate is 15%, compounded annually.

Calculating Present Value of Each Installment

To find the present value (PV) of a future payment (\(F\)) that will be received after \(n\) years at an annual interest rate (\(r\)) compounded annually, we use the following formula:

\(PV = \frac{F}{(1+r)^n}\)

Let's apply this to our given values:

  • Future Payment (\(F\)) = Rs. 5,819 (this is the value of each installment)
  • Annual Rate of Interest (\(r\)) = 15% = 0.15

Present Value of the First Installment

The first installment is paid at the end of the first year. So, for this installment, \(n=1\).

\(PV_1 = \frac{\text{Installment Amount}}{(1+\text{Rate})^1}\)

\(PV_1 = \frac{5819}{(1+0.15)^1}\)

\(PV_1 = \frac{5819}{1.15}\)

\(PV_1 = 5060\)

Present Value of the Second Installment

The second installment is paid at the end of the second year. So, for this installment, \(n=2\).

\(PV_2 = \frac{\text{Installment Amount}}{(1+\text{Rate})^2}\)

\(PV_2 = \frac{5819}{(1+0.15)^2}\)

\(PV_2 = \frac{5819}{(1.15)^2}\)

\(PV_2 = \frac{5819}{1.3225}\)

\(PV_2 = 4400\)

Principal Loan Amount Calculation

The original principal loan amount is the sum of the present values of all installments. This represents the total value of the loan at the beginning, before any payments were made.

\(\text{Principal Loan Amount} = PV_1 + PV_2\)

\(\text{Principal Loan Amount} = 5060 + 4400\)

\(\text{Principal Loan Amount} = 9460 \text{ Rs.}\)

Total Amount Paid Calculation

The total amount paid by the borrower is the sum of all the installments paid over the repayment period.

\(\text{Total Amount Paid} = \text{Number of Installments} \times \text{Each Installment Amount}\)

\(\text{Total Amount Paid} = 2 \times 5819\)

\(\text{Total Amount Paid} = 11638 \text{ Rs.}\)

Interest Charged Calculation

The total interest charged on the loan is the difference between the total amount the borrower paid back and the initial principal loan amount.

\(\text{Total Interest Charged} = \text{Total Amount Paid} - \text{Principal Loan Amount}\)

\(\text{Total Interest Charged} = 11638 - 9460\)

\(\text{Total Interest Charged} = 2178 \text{ Rs.}\)

Summary of Loan Repayment
Description Amount (Rs.)
Present Value of 1st Installment 5060
Present Value of 2nd Installment 4400
Principal Loan Amount 9460
Total Amount Paid (2 x 5819) 11638
Total Interest Charged 2178

The total interest charged for this loan is Rs. 2,178.

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Important Questions from Miscellaneous

  1. A stone is thrown horizontally from the top of a 20 m high building with a speed of 12 m/s. It hits the ground at a distance R from the building. Taking g = 10 m/s2 and neglecting air resistance will give :

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  3. A railway wagon (open at the top) of mass M1 is moving with speed v1 along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M2 and speed becomes v2. Taking the rain to be falling vertically and the water stationery inside the wagon, the relation between the two speeds v1 and v2 is :

  4. Consider the following statements:

    1. Distance between the longitudes becomes zero on North Pole and South Pole.

    2. Distance between the longitudes is maximum on the Equator.

    3. Number of longitudes is more than number of latitudes.

    Which of the statements given above is/are correct?

  5. One block of 2⋅0 kg mass is placed on top of another block of 3⋅0 kg mass. The coefficient of static friction between the two blocks is 0⋅2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s2, the maximum value of the frictional force is :

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