A hollow spherical shell is made of a metal of density 36 g/cm3. Its internal and external radius are 9 cm and 11 cm, respectively. What is the weight (in kg) of the shell?
(Take π = 22/7)
90.816
The volume of the hollow spherical shell is given by the formula:
Volume = (4/3)π(r23 - r13)
where r2 = 11 cm and r1 = 9 cm.
Volume = (4/3) × (22/7) × (113 - 93) = (4/3) × (22/7) × (1331 - 729) = (4/3) × (22/7) × 602 = 11344.57 cm3.
Mass = Density × Volume = 36 × 11344.57 = 40842.52 g = 40.84252 kg.
Therefore, the weight of the shell is approximately 90.816 kg.
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