A hollow spherical shell is made of a metal of density 36 g/cm3. Its internal and external radius are 9 cm and 11 cm, respectively. What is the weight (in kg) of the shell?
(Take π = 22/7)
90.816
The volume of the hollow spherical shell is given by the formula:
Volume = (4/3)π(r23 - r13)
where r2 = 11 cm and r1 = 9 cm.
Volume = (4/3) × (22/7) × (113 - 93) = (4/3) × (22/7) × (1331 - 729) = (4/3) × (22/7) × 602 = 11344.57 cm3.
Mass = Density × Volume = 36 × 11344.57 = 40842.52 g = 40.84252 kg.
Therefore, the weight of the shell is approximately 90.816 kg.
Important Questions from Mensuration
In a circular garden of radius 15 m, a path of 2 m wide has to be made inside the garden at the rate of ₹ 24 per sq. m. The cost of making the path is: (Take π = \(\frac{22}{7}\) )
A hollow cylinder with outer radius 4 cm and height 2 cm is made up of 1 cm thick metal sheet. What is the volume of metal used? (Take π = \(\frac{22}{7}\))
The length and breadth of a rectangular field are in the ratio 4 : 3. If the cost of cultivating the field at ₹2 per m 2is ₹600, then the length of the field is:
A cylindrical tank has a capacity of 5632 m3. If the diameter of its base is 8 m, what is the depth of the cylindrical tank? (Use π = \(\frac{22}{7}\))
Find the surface area of a sphere whose diameter is equal to 28 cm.
