A half wavelength dipole is kept in the x-y plane and oriented along 45° from the x-axis. Determine the direction of null in the radiation pattern for 0 ≤ Φ ≤ π. Here the angle θ (0 ≤ θ ≤ π) is measured from the z-axis, and the angle Φ (0 ≤ Φ ≤ 2π) is measured from the x-axis in the x-y plane.
θ = 90°, Φ = 45°
A half-wavelength dipole antenna is a fundamental antenna type widely used in various applications. Its radiation pattern is distinct and understanding it is crucial for antenna design and analysis.
The radiation pattern of a half-wavelength dipole is characterized by a "doughnut" or toroidal shape. This means that the radiation is strongest in directions perpendicular to the antenna's axis and weakest (nulls) along the antenna's axis itself.
The question specifies that the half-wavelength dipole is kept in the x-y plane and oriented along 45° from the x-axis. Let's break down what this means in terms of spherical coordinates ($\theta$, $\Phi$):
As established, the nulls of a half-wavelength dipole radiation pattern occur precisely along the antenna's axis.
Given that the dipole's axis is oriented at:
Then, the direction of a null in the radiation pattern will also be along this specific orientation.
The far-field electric field strength of a half-wavelength dipole is proportional to $\sin(\Psi)$, where $\Psi$ is the angle measured from the antenna's axis. Nulls occur when $\sin(\Psi) = 0$, which means $\Psi = 0$ or $\Psi = \pi$. These angles correspond to directions *along* the antenna's axis.
Since the question asks for the null direction for $0 \le \Phi \le \pi$, the relevant null direction is $(\theta = 90^\circ, \Phi = 45^\circ)$. The other null would be at $(\theta = 90^\circ, \Phi = 225^\circ)$, which is outside the specified range for $\Phi$.
Based on the antenna's orientation and the characteristics of a half-wavelength dipole's radiation pattern, the null direction is where the observer is directly in line with the antenna's length.
For an antenna in the x-y plane oriented at $\Phi = 45^\circ$, the null direction is indeed:
$\theta = 90^\circ$, $\Phi = 45^\circ$
This corresponds to the direction where the dipole antenna itself is physically located in the x-y plane, 45 degrees from the x-axis.
The Magnetic field inside a solenoid
In standard TV receiving antenna the dipole element is