A group of numbers/symbols is coded using letter codes as per the codes given below and the conditions that follow. The correct combination of codes following the conditions is your answer. Note: If none of the conditions apply, then the codes for the respective number/symbol are to be followed directly as given in the table. Conditions: (i) If both the second and third elements are perfect squares, the codes for these two (the second and third elements) are to be interchanged. (ii) If the first element and the third element are even numbers, these two (the first and third elements) are to be coded as &. (iii) If both the second and third elements are multiples of 3, the third element is to be coded as the code for the second element. What will be the code for the following group? $96@7Numbers/symbols % 8 2 $ 6 3 + 7 @ 9 * 5 # 4 Codes S D R P K H L G B U C N W Q
PUUBG
Step 1: Identify Initial Codes
The group is $96@7. Map each element to its corresponding code from the provided table:
- $ → P
- 9 → U
- 6 → K
- @ → B
- 7 → G
The initial code sequence is PUKBG.
Step 2: Evaluate Conditions
We evaluate the given conditions based on the elements of the group $96@7:
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Condition (i): Checks if the second (9) and third (6) elements are perfect squares.
9 is a perfect square since $9 = 3^2$. However, 6 is not a perfect square. Therefore, this condition is not met.
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Condition (ii): Checks if the first element ($) and the third element (6) are even numbers.
The first element is '$', which is a symbol and not an even number. Therefore, this condition is not met.
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Condition (iii): Checks if the second (9) and third (6) elements are multiples of 3.
9 is a multiple of 3 ($9 = 3 \times 3$). 6 is also a multiple of 3 ($6 = 3 \times 2$). Since both elements satisfy the condition, this condition is met.
Step 3: Apply Condition and Finalize Code
Condition (iii) is met. We apply its rule: "the third element is to be coded as the code for the second element".
- The code for the second element (9) is U.
- The third element (6) initially had the code K.
- According to the rule, we replace the code for the third element (K) with the code for the second element (U).
Starting with the initial code PUKBG, and applying the change from condition (iii), the code for the third position changes from K to U. The final code becomes PUUBG.
Important Questions from Input Output
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