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Question

A group of numbers and symbols is coded using letter codes as per the codes given below and the conditions that follow. Study the given codes and conditions and answer the question that follows.
Note: If none of the conditions apply, then codes for the respective number/symbol are to be followed directly as given in the table.
 

Number/symbol6@85$&3%#7+942
CodeFGHNLKCQZPRBUE


Conditions:
If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.
If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©.
If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
What will be the code for the following group?
5 3 + 4

The correct answer is

© C R ©

Number Group Coding: 5 3 + 4

The task is to determine the correct code for the sequence of numbers and symbols "5 3 + 4" based on a provided set of rules and a mapping table.

Provided Codes

The codes for individual numbers and symbols are given as follows:

Number/SymbolCode
5N
3R
+C
4U

Coding Conditions Explained

There are specific conditions that modify the coding process:

  • Condition 1: If the first element is a symbol and the last element is a number, their codes are interchanged.
  • Condition 2: If the first element is an odd number and the last element is an even number, the codes for both the first and last elements become '©'.
  • Condition 3: If both the second and third elements are perfect squares, the code for the third element is replaced by the code for the second element.

If none of these conditions apply to a particular element or pair, the direct code from the table is used.

Conditions Applied to the Group 5 3 + 4

Let's analyze the group "5 3 + 4" based on the conditions:

  • First element: 5 (This is an odd number).
  • Second element: 3 (This is a number, not a perfect square).
  • Third element: + (This is a symbol, not a number, and thus not a perfect square).
  • Last element: 4 (This is an even number).

Checking the conditions:

  • Condition 1 Check: The first element (5) is a number, not a symbol. So, Condition 1 does not apply.
  • Condition 2 Check: The first element (5) is an odd number, and the last element (4) is an even number. Therefore, Condition 2 applies. According to this condition, both 5 and 4 will be coded as '©'.
  • Condition 3 Check: The second element (3) is not a perfect square. The third element (+) is not even a number. So, Condition 3 does not apply.

Coding Steps for 5 3 + 4

Applying the rules and conditions step-by-step:

  • First Element (5): Condition 2 applies because it's an odd number and the last element is even. The code for 5 becomes '©'.
  • Second Element (3): No conditions affect this element. Its code remains 'R' as per the table.
  • Third Element (+): No conditions affect this element. Its code remains 'C' as per the table.
  • Last Element (4): Condition 2 applies because it's an even number and the first element is odd. The code for 4 becomes '©'.

Final Code Determination

Combining the codes for each element after applying the conditions:

  • 5 -> ©
  • 3 -> R
  • + -> C
  • 4 -> ©

The final code for the group "5 3 + 4" is © C R ©.

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Important Questions from Conditional Matrix

  1. Select the set in which the numbers are related in the same way as are the numbers of the following sets.

    (30, 14, 8)

    (84, 12, 36)

  2. Select the option in which the numbers are related in the same way as are the numbers of the following sets.

    (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 – Operations on 13 such as adding /deleting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)

    (24, 8, 96)

    (36, 4, 72)

  3. What is the value of input if only signal AA and BB is taken into account?

  4. What is the correct option if only signal CC is taken into account?

  5. What is the correct option if both signals AA and DD is taken as input?

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