A group of numbers and symbols is coded using letter codes as per the codes given below and the conditions that follow. Study the given codes and conditions and answer the question that follows.
Note: If none of the conditions apply, then codes for the respective number/symbol are to be followed directly as given in the table.
Number/symbol 2 @ 9 5 $ & 3 % # 7 + 4 8 6 Code D B A M L E C Q D P R B U K
Conditions:
If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.
If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©.
If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
What will be the code for the following group?
@357
Decoding the Group @357 Using Letter Codes
The task is to determine the code for the sequence "@357" based on a given table of number/symbol codes and a set of specific conditions. We need to carefully apply these rules.
Identifying Elements and Base Codes
First, let's break down the group "@357" into its individual elements and find their corresponding codes from the provided table:
- The group is: @357
- Elements are: '@', '3', '5', '7'.
Looking at the code table:
| Number/Symbol | Code |
|---|---|
| @ | B |
| 3 | C |
| 5 | M |
| 7 | P |
Based on direct mapping, the initial sequence of codes for "@357" would be B C M P.
Evaluating the Conditions for Coding
Next, we must examine the three given conditions to see if any apply to the group "@357".
Analysis of Condition 1: Symbol First, Number Last
Condition stated: If the first element is a symbol and the last a number, the codes for these two elements (the first and the last) are to be interchanged.
- Check the first element: '@' is a symbol. This part of the condition is TRUE.
- Check the last element: '7' is a number. This part of the condition is TRUE.
Since both requirements are met, this condition applies. We need to interchange the codes for '@' and '7'.
- The code for '@' is B.
- The code for '7' is P.
- After interchanging, '@' will be coded as P, and '7' will be coded as B.
Applying this change to the initial code B C M P, the sequence becomes P C M B.
Analysis of Condition 2: Odd Number First, Even Number Last
Condition stated: If the first element is an odd number and the last an even number, the first and last elements are to be coded as '©'.
- Check the first element: '@' is a symbol, not an odd number.
As the first element is not an odd number, this condition does not apply to the group "@357".
Analysis of Condition 3: Perfect Squares Check
Condition stated: If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
- Check the second element: '3'. Is '3' a perfect square? No (perfect squares are 1, 4, 9, 16...).
Since the second element ('3') is not a perfect square, this condition does not apply.
Determining the Final Code
Only Condition 1 was applicable. We applied the interchange rule for the first element ('@') and the last element ('7').
- The code for '@' becomes P.
- The code for '3' remains C.
- The code for '5' remains M.
- The code for '7' becomes B.
Combining these, the final code for the group "@357" is PCMB.
Important Questions from Conditional Matrix
Select the set in which the numbers are related in the same way as are the numbers of the following sets.
(30, 14, 8)
(84, 12, 36)
Select the option in which the numbers are related in the same way as are the numbers of the following sets.
(NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits. E.g. 13 – Operations on 13 such as adding /deleting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
(24, 8, 96)
(36, 4, 72)
What is the value of input if only signal AA and BB is taken into account?
What is the correct option if only signal CC is taken into account?
What is the correct option if both signals AA and DD is taken as input?
