A graded indexed optical fiber has a parabolic refractive index profile (α = 2). If the fiber has a numerical aperture = 0.22 the total number of guided modes at a wavelength of 1310 nm is given by:
174
This question asks us to determine the total number of guided modes in a graded index optical fiber with a specific parabolic refractive index profile, given its numerical aperture and the wavelength of light.
Let's break down the important terms:
For a graded index fiber with a parabolic refractive index profile (\(\alpha=2\)), the total number of guided modes \(M\) is approximately given by the formula related to the V-number:
\[ M \approx \frac{V^2}{4} \]
The V-number (also known as the normalized frequency) for an optical fiber is given by:
\[ V = \frac{2\pi a}{\lambda} \text{NA} \]
where:
We are given the following information:
The core radius \(a\) is not directly given in the question. However, graded index fibers with a parabolic profile often have standard core diameters. A common standard for graded index fiber is a 50 µm core diameter. Let's assume the core diameter is 50 µm.
Assumed Core Diameter = 50 µm
Assumed Core Radius (\(a\)) = \(\frac{50 \text{ µm}}{2} = 25 \text{ µm} = 25 \times 10^{-6}\) m
Now, we can calculate the V-number:
\[ V = \frac{2\pi \times (25 \times 10^{-6} \text{ m})}{1310 \times 10^{-9} \text{ m}} \times 0.22 \]
\[ V = \frac{50\pi \times 10^{-6}}{1310 \times 10^{-9}} \times 0.22 \]
\[ V = \frac{50\pi}{1310 \times 10^{-3}} \times 0.22 \]
\[ V = \frac{50\pi}{1.31} \times 0.22 \]
\[ V \approx \frac{157.08}{1.31} \times 0.22 \]
\[ V \approx 119.9 \times 0.22 \]
\[ V \approx 26.38 \]
Next, we calculate the number of guided modes \(M\) using the formula for \(\alpha=2\):
\[ M \approx \frac{V^2}{4} \]
\[ M \approx \frac{(26.38)^2}{4} \]
\[ M \approx \frac{695.91}{4} \]
\[ M \approx 173.98 \]
The calculated number of modes is approximately 173.98. Since the number of modes must be an integer, we round this value to the nearest integer, which is 174.
Let's compare our calculated result with the given options:
Our calculated value of 174 matches Option 1.
Based on the assumption of a standard 50 µm core diameter for the graded index fiber with a parabolic profile, the total number of guided modes at a wavelength of 1310 nm with a numerical aperture of 0.22 is approximately 174.
| Concept | Description | Relevant Formula (\(\alpha=2\) Graded Index) |
|---|---|---|
| Numerical Aperture (NA) | Measures light acceptance angle | Related to index difference and core index |
| Wavelength (\(\lambda\)) | Wavelength of light signal | Used in V-number calculation |
| Core Radius (\(a\)) | Radius of the fiber core | Used in V-number calculation |
| V-number | Normalized frequency, indicates how many modes a fiber can support | \( V = \frac{2\pi a}{\lambda} \text{NA} \) |
| Number of Modes (\(M\)) | Total number of guided paths for light | \( M \approx \frac{V^2}{4} \) |
Graded index fibers are designed to improve performance compared to step index fibers, particularly in terms of bandwidth. The varying refractive index profile causes light rays that travel further from the core axis (following longer geometric paths) to travel through regions of lower refractive index, where light propagates faster. This compensates for the longer path length, allowing different modes to arrive at the fiber end at roughly the same time, thereby reducing modal dispersion.
The number of modes a fiber can support is inversely proportional to the square of the wavelength. This is why using longer wavelengths (like 1310 nm or 1550 nm) is preferred for high-speed, long-distance communication, as it reduces the number of modes and thus reduces modal dispersion. Single-mode fibers, which support only one mode, have very small core diameters (typically 8-10 µm) and operate at longer wavelengths to achieve very high bandwidth.
The formula for the number of modes \(M\) for a graded-index fiber with profile parameter \(\alpha\) is generally given as \(M \approx \frac{\alpha}{\alpha+2} \frac{V^2}{2}\). For a step-index fiber, \(\alpha \rightarrow \infty\), leading to \(M \approx \frac{V^2}{2}\). For a parabolic profile, \(\alpha=2\), leading to \(M \approx \frac{2}{2+2} \frac{V^2}{2} = \frac{1}{2} \frac{V^2}{2} = \frac{V^2}{4}\), which is consistent with our calculation.
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