A gas having a negative Joule-Thompson effect (μ < 0), when throttled will
Become warmer
The question asks what happens to a gas when it is throttled and has a negative Joule-Thompson effect. Let's first understand the Joule-Thompson effect.
The Joule-Thompson effect describes the temperature change of a real gas or liquid when it expands adiabatically through a valve or porous plug from a high-pressure region to a low-pressure region, a process known as throttling. This process occurs at constant enthalpy (isenthalpic).
The key parameter for this effect is the Joule-Thompson coefficient, denoted by $\mu$. It is defined as the partial derivative of temperature with respect to pressure at constant enthalpy:
$$ \mu = \left( \frac{\partial T}{\partial P} \right)_H $$
Here, $T$ is the temperature, $P$ is the pressure, and $H$ is the enthalpy.
The question states that the gas has a negative Joule-Thompson effect, which means its Joule-Thompson coefficient is negative ($μ < 0$).
According to the definition of the Joule-Thompson coefficient, if $μ < 0$, then $\left( \frac{\partial T}{\partial P} \right)_H$ is negative. Since throttling involves a decrease in pressure ($\Delta P$ is negative), the change in temperature ($\Delta T$) must be positive for the ratio to be negative:
$$ \Delta T = \mu \times \Delta P $$
If $μ < 0$ and $\Delta P < 0$, then $\Delta T$ must be positive ($ ( - ) \times ( - ) = ( + ) $).
Therefore, when a gas with a negative Joule-Thompson effect is throttled, its temperature increases.
In summary:
| Joule-Thompson Coefficient ($\mu$) | Temperature Change During Throttling | Result |
|---|---|---|
| $\mu > 0$ | Decreases ($\Delta T < 0$ for $\Delta P < 0$) | Cooling |
| $\mu < 0$ | Increases ($\Delta T > 0$ for $\Delta P < 0$) | Warming |
| $\mu = 0$ | No change ($\Delta T = 0$ for $\Delta P < 0$) | Constant Temperature |
Since the gas has a negative Joule-Thompson effect ($μ < 0$), it will become warmer when throttled.
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