All Exams Test series for 1 year @ ₹349 only
Question

A first-order reaction has a half-life of 693 seconds. What will be its rate constant?

The correct answer is

0.001 sec⁻¹

Understanding First-Order Reaction Kinetics and Half-Life

Chemical kinetics is the study of reaction rates. For a chemical reaction, the rate constant (\(k\)) is a proportionality constant that relates the reaction rate to the concentrations of reactants. The order of a reaction describes how the rate depends on the concentration of reactants. A first-order reaction is one where the reaction rate is directly proportional to the concentration of one reactant.

Calculating Rate Constant from Half-Life for a First-Order Reaction

The half-life (\(t_{1/2}\)) of a reaction is the time required for the concentration of a reactant to decrease to half of its initial value. For a first-order reaction, the half-life is constant and independent of the initial concentration of the reactant. There is a specific relationship between the half-life (\(t_{1/2}\)) and the rate constant (\(k\)) for a first-order reaction. This relationship is given by the formula:

\(t_{1/2} = \frac{0.693}{k}\)

We are given that the first-order reaction has a half-life of 693 seconds. We need to find its rate constant (\(k\)). We can rearrange the formula to solve for \(k\):

\(k = \frac{0.693}{t_{1/2}}\)

Step-by-Step Calculation

Given:

  • Half-life, \(t_{1/2} = 693\) seconds

We need to find the rate constant, \(k\).

Using the formula for a first-order reaction:

\(k = \frac{0.693}{t_{1/2}}\)

Substitute the given value of \(t_{1/2}\):

\(k = \frac{0.693}{693 \text{ seconds}}\)

Now, perform the calculation:

\(k = 0.001 \text{ sec}^{-1}\)

The unit for the rate constant of a first-order reaction is typically time\(\text{⁻¹}\) (e.g., s\(\text{⁻¹}\), min\(\text{⁻¹}\), hr\(\text{⁻¹}\)). In this case, since the half-life is in seconds, the rate constant will have units of seconds\(\text{⁻¹}\).

Comparing with Options

The calculated rate constant is 0.001 sec\(\text{⁻¹}\). Let's look at the options provided:

  1. 0.001 sec\(\text{⁻¹}\)
  2. 1 sec\(\text{⁻¹}\)
  3. 0.001 sec\(\text{⁻¹}\)
  4. 0.1 sec\(\text{⁻¹}\)

Our calculated value matches option 1 and option 3.

Revision Table: First-Order Reaction Key Formulas

Concept Formula Notes
Rate Law \(\text{Rate} = k[\text{A}]\) For reaction A \(\rightarrow\) Products
Integrated Rate Law \(\ln[\text{A}]_t = \ln[\text{A}]_0 - kt\) \([\text{A}]_t\) is concentration at time t, \([\text{A}]_0\) is initial concentration
Integrated Rate Law (Alternative form) \(\ln\left(\frac{[\text{A}]_0}{[\text{A}]_t}\right) = kt\)
Half-Life (\(t_{1/2}\)) \(t_{1/2} = \frac{0.693}{k}\) Independent of initial concentration
Rate Constant (\(k\)) from Half-Life \(k = \frac{0.693}{t_{1/2}}\) Derived from the half-life formula

Additional Information on Reaction Order and Half-Life

The relationship between half-life and rate constant depends on the order of the reaction. While the half-life of a first-order reaction is constant, this is not true for other reaction orders.

  • Zero-Order Reaction: The half-life of a zero-order reaction is dependent on the initial concentration. The formula is \(t_{1/2} = \frac{[\text{A}]_0}{2k}\).
  • Second-Order Reaction: The half-life of a second-order reaction is also dependent on the initial concentration. The formula is \(t_{1/2} = \frac{1}{k[\text{A}]_0}\).

This makes the first-order reaction's constant half-life a unique and important characteristic.

Was this answer helpful?

Important Questions from Chemical Kinetics

  1. A reaction takes 30 minutes to complete 50% of the reaction and takes 45 minutes to complete 75% of the reaction. The order of the reaction is:

  2. Ferric oxide in blast furnace's upper half is mainly reduced by:

  3. If time taken for a first-order reaction to get 90% complete is 24 min, its t99.9% will be:

  4. Match the Items List-I and List-II:

    List-IList-II
    (A) Instantaneous Rate(I) Rate constant
    (B) Average Rate(II) Rate law
    (C) Mathematical expression for rate of reaction in terms of concentration of reactants(III) Short interval of time
    (D) Rate of reaction for zero-order reaction is equal to(IV) Long direction of time

    Choose the correct answer from the options given below:

  5. product formed is:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App