A first-order reaction has a half-life of 693 seconds. What will be its rate constant?
0.001 sec⁻¹
Chemical kinetics is the study of reaction rates. For a chemical reaction, the rate constant (\(k\)) is a proportionality constant that relates the reaction rate to the concentrations of reactants. The order of a reaction describes how the rate depends on the concentration of reactants. A first-order reaction is one where the reaction rate is directly proportional to the concentration of one reactant.
The half-life (\(t_{1/2}\)) of a reaction is the time required for the concentration of a reactant to decrease to half of its initial value. For a first-order reaction, the half-life is constant and independent of the initial concentration of the reactant. There is a specific relationship between the half-life (\(t_{1/2}\)) and the rate constant (\(k\)) for a first-order reaction. This relationship is given by the formula:
\(t_{1/2} = \frac{0.693}{k}\)
We are given that the first-order reaction has a half-life of 693 seconds. We need to find its rate constant (\(k\)). We can rearrange the formula to solve for \(k\):
\(k = \frac{0.693}{t_{1/2}}\)
Given:
We need to find the rate constant, \(k\).
Using the formula for a first-order reaction:
\(k = \frac{0.693}{t_{1/2}}\)
Substitute the given value of \(t_{1/2}\):
\(k = \frac{0.693}{693 \text{ seconds}}\)
Now, perform the calculation:
\(k = 0.001 \text{ sec}^{-1}\)
The unit for the rate constant of a first-order reaction is typically time\(\text{⁻¹}\) (e.g., s\(\text{⁻¹}\), min\(\text{⁻¹}\), hr\(\text{⁻¹}\)). In this case, since the half-life is in seconds, the rate constant will have units of seconds\(\text{⁻¹}\).
The calculated rate constant is 0.001 sec\(\text{⁻¹}\). Let's look at the options provided:
Our calculated value matches option 1 and option 3.
| Concept | Formula | Notes |
|---|---|---|
| Rate Law | \(\text{Rate} = k[\text{A}]\) | For reaction A \(\rightarrow\) Products |
| Integrated Rate Law | \(\ln[\text{A}]_t = \ln[\text{A}]_0 - kt\) | \([\text{A}]_t\) is concentration at time t, \([\text{A}]_0\) is initial concentration |
| Integrated Rate Law (Alternative form) | \(\ln\left(\frac{[\text{A}]_0}{[\text{A}]_t}\right) = kt\) | |
| Half-Life (\(t_{1/2}\)) | \(t_{1/2} = \frac{0.693}{k}\) | Independent of initial concentration |
| Rate Constant (\(k\)) from Half-Life | \(k = \frac{0.693}{t_{1/2}}\) | Derived from the half-life formula |
The relationship between half-life and rate constant depends on the order of the reaction. While the half-life of a first-order reaction is constant, this is not true for other reaction orders.
This makes the first-order reaction's constant half-life a unique and important characteristic.
A reaction takes 30 minutes to complete 50% of the reaction and takes 45 minutes to complete 75% of the reaction. The order of the reaction is:
Ferric oxide in blast furnace's upper half is mainly reduced by:
If time taken for a first-order reaction to get 90% complete is 24 min, its t99.9% will be:
Match the Items List-I and List-II:
| List-I | List-II |
|---|---|
| (A) Instantaneous Rate | (I) Rate constant |
| (B) Average Rate | (II) Rate law |
| (C) Mathematical expression for rate of reaction in terms of concentration of reactants | (III) Short interval of time |
| (D) Rate of reaction for zero-order reaction is equal to | (IV) Long direction of time |
Choose the correct answer from the options given below:
product formed is: