The question asks for the magnitude of the displacement of a farmer from his starting point after walking for a specific duration along the boundary of a square field.
Square Field Displacement Calculation
First, let's determine the total time the farmer walked and how many rounds he completed.
- Field side length: $11 \text{ m}$
- Time to complete one round: $20 \text{ s}$
- Total walking time: $3 \text{ minutes}$ and $20 \text{ seconds}$
Total Walking Time in Seconds
Convert the total walking time entirely into seconds:
Total time = $(3 \times 60 \text{ s}) + 20 \text{ s} = 180 \text{ s} + 20 \text{ s} = 200 \text{ s}$
Number of Rounds Completed
Calculate the number of full rounds completed by dividing the total walking time by the time taken for one round:
Number of rounds = $\frac{\text{Total walking time}}{\text{Time per round}} = \frac{200 \text{ s}}{20 \text{ s}} = 10 \text{ rounds}$
Understanding Displacement
Displacement is the shortest distance between an object's initial and final position. It is a vector quantity, meaning it has both magnitude and direction.
In this scenario, the farmer walks along the boundary of the square field. Completing one full round means returning to the exact starting point.
Final Displacement Calculation
Since the farmer completed exactly 10 full rounds, his final position is the same as his starting point.
Therefore, the magnitude of his displacement is $0 \text{ m}$.
Important Questions from Motion
The motion of a particle of mass m is described by the relation, y = ut - 1⁄2 gt2, where u is the initial velocity of the particle. The force acting on the particle is
The motion of ______ body is an example of uniformly accelerated motion.
- in a particular direction is velocity.
Motion of an object is if its velocity is constant.
The motion of the body moving along a circular path is an example of ______.
