A family has several children. Each boy in this family has as many sisters as brothers, but each girl has twice as many brothers as sisters. How many brothers and sisters are there?
4 and 3
This problem involves figuring out the number of boys and girls in a family based on clues about their siblings. We can solve this using algebra.
Let's define:
B = the total number of boys in the family.G = the total number of girls in the family.We are given two main conditions:
B - 1GB - 1 = GBG - 1B = 2 * (G - 1)Now we have a system of two equations:
G = B - 1B = 2(G - 1)We can use substitution to solve for B and G. Let's substitute the first equation into the second one:
Substitute G from equation (1) into equation (2):
B = 2((B - 1) - 1)
Simplify the expression inside the parentheses:
B = 2(B - 2)
Distribute the 2:
B = 2B - 4
To solve for B, let's rearrange the equation:
Subtract B from both sides:
0 = B - 4
Add 4 to both sides:
B = 4
So, there are 4 boys in the family.
Now, let's find the number of girls using the first equation (G = B - 1):
G = 4 - 1
G = 3
So, there are 3 girls in the family.
Let's check if our numbers (4 boys, 3 girls) satisfy the original conditions:
4 - 1 = 3 brothers and 3 sisters. Does he have as many sisters as brothers? Yes, 3 = 3.4 brothers and 3 - 1 = 2 sisters. Does she have twice as many brothers as sisters? Yes, 4 = 2 * 2.Both conditions are met.
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